Here is the question: "A ball is dropped into a cylinder filled with paint. The process is then repeated with a ball of the same diameter but twice the mass. How would the terminal velocity differ and why?". I understand that in order to reach terminal velocity, the weight (W) must equal the drag (D) + upthrust (U) and initially, the drag is much greater than the weight, so the ball decelerates. I also understand that the ball has a larger mass and so greater weight. What does this mean for the terminal velocity, however? Does it mean that, as the ball has a greater weight, the terminal velocity would be reached sooner as W = U + D. D is initially much larger than weight so must decrease and as W is a larger value, it decreases such that U+D = W quicker? However I've always been taught that mass is directly proportional to the terminal velocity. Help please.?