This discussion is now closed.
Scroll to see replies
\displaystyle \int \dfrac {x}{x+1}\\[br][br][br]= \displaystyle \int \dfrac {x+1-1}{x+1} \\[br][br][br]= \displaystyle \int \dfrac {x+1}{x+1} - \dfrac {1}{x+1}\\[br][br][br]= x - \ln (x+1)[br]
\displaystyle\int \dfrac {x}{x+1}\\\\[br][br][br]= \displaystyle\int \dfrac {x+1-1}{x+1}\\\\[br][br][br]= \displaystyle\int \dfrac {x+1}{x+1} - \dfrac {1}{x+1}\\\\[br][br][br]= x - \ln (x+1)[br]
\pi\displaystyle\int x^{2} dy \\[br]
Last reply 1 minute ago
SQA Higher Physics - Paper 2 - 25th April 2024 [Exam Chat]Last reply 28 minutes ago
SQA Nat 5 English - Critical Reading - 7th May 2024 [Exam Chat]Last reply 4 days ago
SQA Higher Mathematics - Paper 1 Non-calculator - 13th May 2024 [Exam Chat]Last reply 1 week ago
SQA Higher English - Critical Reading - 9th May 2024 [Exam Chat]Last reply 1 minute ago
SQA Higher Physics - Paper 2 - 25th April 2024 [Exam Chat]Last reply 28 minutes ago
SQA Nat 5 English - Critical Reading - 7th May 2024 [Exam Chat]Last reply 4 days ago
SQA Higher Mathematics - Paper 1 Non-calculator - 13th May 2024 [Exam Chat]Last reply 1 week ago
SQA Higher English - Critical Reading - 9th May 2024 [Exam Chat]