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Maths C2 logs question

Hey guys I was doing some revision for logs and struggled to understand the answer for this question and seem to get it wrong after trying multiple times. Any help would be much appreciated! Thanks!

Question: Given the simultaneous equation
2^x( power of x)=3^y
x+y=1

Show that x=log3/log6
Reply 1
Original post by Basdemraj
Hey guys I was doing some revision for logs and struggled to understand the answer for this question and seem to get it wrong after trying multiple times. Any help would be much appreciated! Thanks!

Question: Given the simultaneous equation
2^x( power of x)=3^y
x+y=1

Show that x=log3/log6


Take logs of the first equation. You then simply have a standard pair of simultaneous equations to solve.
x+y=1,xlog(2)=ylog(3)x+y=1, \quad x\log(2)=y\log(3).
Reply 2
Original post by joostan
Take logs of the first equation. You then simply have a standard pair of simultaneous equations to solve.
x+y=1,xlog(2)=ylog(3)x+y=1, \quad x\log(2)=y\log(3).

Thank you
Reply 3
Original post by Basdemraj
Thank you

It will probably be worth noting that:
a+bc=ac+bca+\dfrac{b}{c}=\dfrac{ac+b}{c}.

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