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Stuck with Math question

EleanorS14

Solve 7(k-3)=3k-5

Thanks :smile:

Reply 1

Zacken

Original post by EleanorS14

Solve 7(k-3)=3k-5

Thanks :smile:

What have you tried?

Try expanding the LHS first:

7(k-3) = 7k - 21

So we have

7(k-3) = 3k-5 \iff 7k - 21 = 3k - 5

Now put all the k's one one side and all the constants on the other.

Reply 2

EleanorS14

Thanks

Would it be like this 7-21 = 3 - 5
-14=-2
(Sorry I'm really bad at maths.)

Reply 3

EleanorS14

Original post by Zacken

What have you tried?

Try expanding the LHS first:

7(k-3) = 7k - 21

So we have

7(k-3) = 3k-5 \iff 7k - 21 = 3k - 5

Now put all the k's one one side and all the constants on the other.

Thanks

Zacken;64488879
Would it be like this 7-21 = 3 - 5
-14=-2
(Sorry I'm really bad at maths.)

(edited 7 years ago)

Reply 4

rohit301099

Original post by EleanorS14

Solve 7(k-3)=3k-5

Thanks :smile:

Um, first expand the brackets

7k-21= 3k-5

Then collect the like terms together

7k-3k=-5+21

Then simplify
4k=16
k=16/4
k=4

hope it helps

Reply 5

EleanorS14

Original post by rohit301099

Um, first expand the brackets

7k-21= 3k-5

Then collect the like terms together

7k-3k=-5+21

Then simplify
4k=16
k=16/4
k=4

hope it helps

Thankyou.I understand now.

Reply 6

Zacken

Original post by EleanorS14

Thankyou.I understand now.

Glad it's sorted now. :h:

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