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2016 Unofficial M1 Mark Scheme? 2016

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for question 2 part b i got 15.7N because i did F=2(0.5)+1.5(9.8), how many marks is that
Original post by E1Ephan7
I completely guessed 7a) F=2.5i and forgot to write j component. Showed no working. How many marks could i get??

Zero
Any working out for the 0.74 question
Marks:
Question 1 A -3, B-3, C-4
Question 2 A-3, B-3
Question 3 A-7
Question 4 A-4, B-8
Question 5 A-10
Question 6 A-7
Question 7 A-7, B-4
Question 8 A-8, B-4
Reply 64
I got 0.65 for the coefficient of friction wtfff i thought i aced it :frown:
how many marks was 1c worth?
Original post by Khaddad
I got 0.65 for the coefficient of friction wtfff i thought i aced it :frown:


And I got 0.873
How many marks would I lose for 3sfgs on the coefficient of friction for q5??? i.e 0.727
Reply 68
Original post by VA123
was μ meant to be given to 2sf or is 3sf ok?


3is fine, i gave it to 3 as well
Reply 69
Original post by student bang
And I got 0.873


Rip. At least were not the only ones
Original post by KloppOClock
Message me if anything is wrong.
Also, if anyone remembers how many marks each question was worth, please comment so I can add them on too.

Question 1:

Spoiler

Question 2:

Spoiler

Question 3:

Spoiler

Question 4:

Spoiler

Question 5: (10 Marks)

Spoiler

Question 6: (7 Marks?)

Spoiler

Question 7:

Spoiler

Question 8:

Spoiler




Woo think I only lost about 5 marks,
Original post by student bang
Good luck in life with this attitude


Good luck in life with that name.

And your mark.
What do people estimate the raw mark to be for 90 or 100 UMS
Reply 73
Original post by Verish
Its an AS module, you cant get an A*?


Probably means 90 UMS.
Reply 74
Anyone has the actual questions?
Original post by geniuses
Dear Failures,

I have just realised i have achieved 100% in this exam.

Good luck next year!


Same, but I think its a bit rude to call people failures. I'm sure loads of people did really well and tried their best.
Original post by Ilyas_99
Same, but I think its a bit rude to call people failures. I'm sure loads of people did really well and tried their best.


You and me Bro, we will rule the 7th dimension.
All you had to do is 2Tcos(45), as the forces where at right angles to each other.
Original post by vvlp
For the magnitude of the force on the pulley I didn't do root T^2 + T^2 because i got confused when it said work out the resultant magnitude and it messed me up. I thought the resultant force was the root of ((T-friction)^2 + (weight - T)^2)

Was this stupid of me? I thought 11.47^2 with an angle of 45 from the horizontal was too simple for 4 marks.


Original post by vvlp
For the magnitude of the force on the pulley I didn't do root T^2 + T^2 because i got confused when it said work out the resultant magnitude and it messed me up. I thought the resultant force was the root of ((T-friction)^2 + (weight - T)^2)

Was this stupid of me? I thought 11.47^2 with an angle of 45 from the horizontal was too simple for 4 marks.
Original post by geniuses
You and me Bro, we will rule the 7th dimension.


I'm a girl

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