Higher Maths Help
1. Find out the equation of the tangent to the curve with the equation:
y=4/3 Root x
at the point x =4
2. Find the point on the curbe with equation:
y=2x(power of 2) + 4x - 1
at which teh tangent has a gradient of 12.
y=4/3 Root x
at the point x =4
2. Find the point on the curbe with equation:
y=2x(power of 2) + 4x - 1
at which teh tangent has a gradient of 12.
Original post by JaggySnake95
1. Find out the equation of the tangent to the curve with the equation:
y=4/3 Root x
at the point x =4
2. Find the point on the curbe with equation:
y=2x(power of 2) + 4x - 1
at which teh tangent has a gradient of 12.
y=4/3 Root x
at the point x =4
2. Find the point on the curbe with equation:
y=2x(power of 2) + 4x - 1
at which teh tangent has a gradient of 12.
What have you done so far?
It's easiest to help if we know what you're stuck on, but we really oughtn't do your work for you. 
Some hints
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