C3 January 2013 25/01/2013

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another example would be

(2x-3)/(x-2) so we need to convert in this form 2+(1/x-2)

so can we do
2x/(x-2) - 3/(x-2) and solving

Reply 1181

steve2005

Original post by otrivine

another example would be

(2x-3)/(x-2) so we need to convert in this form 2+(1/x-2)

so can we do
2x/(x-2) - 3/(x-2) and solving

What are you 'solving' ? There is no equation to solve.

Reply 1182

posthumus

Original post by otrivine

yes that is what i was thinking partial fractions right?

so just to check if i used long division i put the x on the outside and the x-2 inside the root

no its the other way round

x-2 | x + 0

x X 1 = x

So 1 goes to the top

-2 x 1 ... -2

0--2 = 2

2 is the remainder

so your answer is 1+ 2/x-2

Reply 1183

kvohra

Original post by otrivine

another example would be

(2x-3)/(x-2) so we need to convert in this form 2+(1/x-2)

so can we do
2x/(x-2) - 3/(x-2) and solving

2x-3/x-2
=(2x-4)/(x-2) + 1/(x-2)
= 2 + 1/(x-2)

Posted from TSR Mobile

Reply 1184

otrivine

Original post by steve2005

What are you 'solving' ? There is no equation to solve.

No we need to convert the form so it would help us to draw the graph and to find the range

Reply 1185

otrivine

Original post by kvohra

2x-3/x-2
=(2x-4)/(x-2) + 1/(x-2)
= 2 + 1/(x-2)

Posted from TSR Mobile

\are my correct then

Reply 1186

AS01

Original post by otrivine

yes that is what i was thinking partial fractions right?

so just to check if i used long division i put the x on the outside and the x-2 inside the root

thats it! partial fraction :biggrin:

no the qsn says x/x-2 so x should be inside and x-2 outside.

Reply 1187

AS01

Original post by otrivine

another example would be

(2x-3)/(x-2) so we need to convert in this form 2+(1/x-2)

so can we do
2x/(x-2) - 3/(x-2) and solving

any qsn of this type use partial fraction its much easier and its easy to find range with that too.

Reply 1188

kvohra

Original post by otrivine

\are my correct then

Yes

Posted from TSR Mobile

Reply 1189

otrivine

Original post by AS01

thats it! partial fraction :biggrin:

no the qsn says x/x-2 so x should be inside and x-2 outside.

its ok i think getting the value that equals the denominator is much easier :smile:

Reply 1190

steve2005

Original post by otrivine

another example would be

(2x-3)/(x-2) so we need to convert in this form 2+(1/x-2)

so can we do
2x/(x-2) - 3/(x-2) and solving

Reply 1191

Padouken

Original post by steve2005

What are you 'solving' ? There is no equation to solve.

Solving the problem, your highness.

Reply 1192

AS01

Original post by otrivine

its ok i think getting the value that equals the denominator is much easier :smile:

what is that?

Reply 1193

otrivine

Original post by AS01

what is that?

thats what Kvohra said?

Reply 1194

otrivine

I think I am over complicating this easy question! just can some one tell me the easiest way please

Reply 1195

posthumus

Original post by otrivine

its ok i think getting the value that equals the denominator is much easier :smile:

Its easy if you figure it out.

But the long division partial fraction thing will always work... but it is easier to make mistakes with, but not much more difficult

Reply 1196

AS01

Original post by otrivine

thats what Kvohra said?

oh okay. I will just stick with what I am doing that's easy way too. Since we have this in C4 as well I better go with that division one :biggrin:

Reply 1197

otrivine

Original post by posthumus

Its easy if you figure it out.

But the long division partial fraction thing will always work... but it is easier to make mistakes with, but not much more difficult