AQA Physics P3 May 23rd 2013 NEW SPEC

What could u say for six marks though;/

They'd split it up into two bullet points,
How does it work?
So uses high freq. etc
Why is it useful?
Saves space etc.

Yeah, the questions are always easy guys. Like ffs, on the 6 marker for chem they asked exactly the same as the spec.

What could i say if i had a six mark question on the motor effect?

You could say:
1. A current flows through a wire causing a small magnetic field.
2. When this wire is put into a magnets field, the magnetic field interact with each other causing a resultant movement.
3. Although this can only happen if the wire is at 90 degrees to the magnet.
4. Depending on the direction of the current and magnetic field, the wire will be pushed in a certain direction.
5. To change the direction of the movement you can change the direction of the current or the direction of the magnetic field.
6. The force of the movement can be increased by a stronger magnetic field or increasing the current.

This would be if they asked for the basic principals of it.

What could u say for six marks though;/

How do you explain the ultrasound how a pulse can be used to detect flaws or changes of density in materials? For 6marks

How do you explain the ultrasound how a pulse can be used to detect flaws or changes of density in materials? For 6marks

The transducer is a device which detects ultrasound waves.
Each pulse from the transducer is partially reflected from the different tissue boundaries in its path. This creates a sequence of reflected pulses from the different boundaries on the monitor, as they arrive back at different times. The transducer is moved across the surface of the body and the pulses are detected by the transducer.
The detected pulses are used to build up an image on the screen of the internal tissue boundaries in the body.

Feel free to add to it,

Can anyone explain transformers to me in REALLY simple terms? Have no idea what they are


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Can anyone explain transformers to me in REALLY simple terms? Have no idea what they are


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Very much doubt they would just give you a 6 marker on a switch mode, more likely to be 3 or 4.
You could say:
Uses very little power when you have no device connected
It operates at a much higher frequency that a normal transformer
Much lighter and smaller, more practical then

s=v×t
(s = distance [metres, m], v = speed [metres per second, m/s], t = time [seconds, s])

refractive index = sin i/sin r
(i = angle of incidence [degrees], r = angle of refraction [degrees])

magnification = image height [metres/centimetres, m/cm]/object height[metres/centimetres, m/cm]

P = 1f
(P = power [Dioptres, D], f = focal length [centimetres, cm])

refractive index = 1/sin c [HT only]
(c = critical angle [degrees])

T = 1f
(T = periodic time, f = frequency [Herz, Hz])

M=F×d
(M = moment of the force [Newton-metres, Nm], F = force [Newtons, N],
d = perpendicular distance from the line of action of the force to the pivot [metres, m])

P = AF
(P = pressure [Pascals, Pa], F = force [Newtons, N], A = cross-sectional area [Metres, m^2])

Vp/Vs = Np/Ns
(Vp = potential difference across the primary coil, Vs = potential difference across the secondary coil, Np = number of turns on the primary coil, Ns = number of turns on the secondary coil)

Vp × lp =Vs × ls
(Vp = potential difference across the primary coil, Ip = current in the primary coil, Vs = potential difference across the secondary coil, Is = current in the secondary coil)


FOR TWO ABOVE;
Potential Difference (V) [volts, V]

FOR ONE ABOVE;
Current (I) [amperes {a.k.a. amps}, A]


Hope this helps



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we get all this in the exam?... RIGHT?!