You are left with an arbitrary constant of integration, so you have to use the other information given in the question to find the value of the constant and thus the equation of the line.
You are left with an arbitrary constant of integration, so you have to use the other information given in the question to find the value of the constant and thus the equation of the line.
That is exactly where I got stuck, I then thought of using the (0,0) coordinates with that method but that didn't give me the right answer and I don't understand why it didn't.. :/
To do this you must first find the equation of the tangent. You would try to find the gradient l. You will find this to be 3 i think. You would use 3 and also the point (0,0) to form an equation of the tanget. You will find this to be y=3x. Next you would sub in 2 to get a y value of 6. Then you would integrate the given equation and subsitute in 2 as the x value and 6 as the y value to find the constant.
To do this you must first find the equation of the tangent. You would try to find the gradient l. You will find this to be 3 i think. You would use 3 and also the point (0,0) to form an equation of the tanget. You will find this to be y=3x. Next you would sub in 2 to get a y value of 6. Then you would integrate the given equation and subsitute in 2 as the x value and 6 as the y value to find the constant.
To do this you must first find the equation of the tangent. You would try to find the gradient l. You will find this to be 3 i think. You would use 3 and also the point (0,0) to form an equation of the tanget. You will find this to be y=3x. Next you would sub in 2 to get a y value of 6. Then you would integrate the given equation and subsitute in 2 as the x value and 6 as the y value to find the constant.