Help with core 1 maths question
Solve the inequality:
9k^2 + 4k - 28 > 0
Thank you
just to add my teacher told me the answers are 14/9 and -2 but I don't know how to get to it
9k^2 + 4k - 28 > 0
Thank you
just to add my teacher told me the answers are 14/9 and -2 but I don't know how to get to it
(edited 8 years ago)
The first step is to solve it as a quadratic equation.
If you treat it like it equals zero to start with and get a quadratic and what k would equal, you can then draw a curved to see which signs, either > or <, should be where the equals sign is.
Mind linking me to the paper you got that from?
Original post by bakedbeans247
Mind linking me to the paper you got that from?
I don't actually have the paper. It was part of a paper put together by my college.
Original post by SecretDuck
The first step is to solve it as a quadratic equation.
I can't actually factorise it though.
Original post by kaclrk
I don't actually have the paper. It was part of a paper put together by my college.
Oh ok then. Well here, i found the answer: http://www.thestudentroom.co.uk/showthread.php?t=1796766
Original post by kaclrk
Solve the inequality:
9k^2 + 4k - 28 > 0
Thank you
just to add my teacher told me the answers are 14/9 and -2 but I don't know how to get to it
9k^2 + 4k - 28 > 0
Thank you
just to add my teacher told me the answers are 14/9 and -2 but I don't know how to get to it
(k+2)(9k-14) - 9k^2+18k-14k-28
k=-2 k=14/9
Original post by bakedbeans247
Oh ok then. Well here, i found the answer: http://www.thestudentroom.co.uk/showthread.php?t=1796766
Thank you!!
Original post by emily132
(k+2)(9k-14) - 9k^2+18k-14k-28
k=-2 k=14/9
k=-2 k=14/9
so would the answer be k<14/9 and k>-2
or just k=14/9 k=-2
Original post by Fatuma-97
so would the answer be k<14/9 and k>-2
or just k=14/9 k=-2
or just k=14/9 k=-2
yeah you would the inequality sign and probably sketch a quick graph to show the values to get all the marks
Original post by emily132
yeah you would the inequality sign and probably sketch a quick graph to show the values to get all the marks
ok thank you
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