Oxford November 2006 Physics Test

I disagree with your answer to 11 d. Bulb d is off because an equal current is flowing from each cell but in opposite directions. I'm not 100% about g though, although I think something similar occurs.

I haven't gone through it thorough but the rest seem ok :smile:

, a very good idea though.

edit: infact thinking about it you have 5 answers when there should be 8.

Reply 3

q 13 I think you would have to extrapolate the graph until it touched the x axis. and then intergrate, because although the rocket is decelerating it is still moving upwards.

q11 I found f to be normal (Parallel circuit)
c to be normal ( two bulbs two batteries therefore normal) :s-smilie:

g to be brighter as you said and h to be normal

q 9 it would be B because D reads the mass remains constant and density decreases, which is obviously incorrect.

Reply 4

RE question 12:
G = 21; R = 14; B = 28 is definitley correct..
Now I can't remember the whole story with 'float with half of their volume exposed' but does that mean that their density is equal to that of the liquid?
If so then...
Volume of cubes =

0.21^3+0.14^3+0.28^3=0.033957m^3

Density = Mass/Volume
Hence 20kg/0.033957m^3 = 589(1s.f.)kgm^3

So err, where is "231.525 (or 1177.96, for some reason igot two answers need to redo q)" coming from :s:

Reply 5

ChrisRH

Hence 20kg/0.033957m^3 = 589(1s.f.)kgm^3

Oh ye I forgot to mention that but I wasnt sure what half in half out meant.

I did get 589kg m^-3 though, because i assumed it meant the densities were equal. :s-smilie:

Reply 6

fisix

Oh ye I forgot to mention that but I wasnt sure what half in half out meant.

I did get 589kg m^-3 though, because i assumed it meant the densities were equal. :s-smilie:

Good luck on wednesday!
I assume you are applying for physics this year? Your sig states medicine last year?

Reply 7

ChrisRH

RE question 12:
G = 21; R = 14; B = 28 is definitley correct..
Now I can't remember the whole story with 'float with half of their volume exposed' but does that mean that their density is equal to that of the liquid?

No, an object floating on a liquid will displace its mass' worth of liquid. Therefore, 20kg of the liquid is displaced by half the total volume of the cubes. I can't be bothered to go through it from there but it's exactly the way you did it, and I got an answer of 1176.

Reply 8

jobo3

1

Is it just me or is everyone else finding the Maths test easier than the Physics one?

I'm just hoping that there won't be any electronics stuff on Weds, and has anyone looked up 'phases of the moon', it's on the sylabus that's all?

Reply 9

Well yeah 589x2 = 1178 =]
Thanks. If the cubes floated just below the surface, so that just the top face of each cube was visible, I assume it would then be 589kgm^3?

Reply 10

jobo, just go through some online GCSE resource, it seems to be adequate for the sample paper. :smile:

Reply 11

I found the maths one much much harder :s-smilie:

maybe its because you do further maths :s-smilie:

ChrisH, ye i did apply for med last year, I got in to Cam but missed my offer :s-smilie:

gutted lol, but I didn't go to my insurance because i really wanna do Physics for the rest of my life

Reply 12

What did people get as answers to the Maths one

I got

1. 3

2. lambda>1

3. couldn't be bothered

4.lots of drwaing

5. 4, root2, 1

6. 64.3845

7. Dunno :s-smilie:

8. 1/6, 5/12

9. dunno :s-smilie:

10. Dunno :s

11. Minimum: 2 y=-15 Maximum: 5 y=66

I told you I found the maths hard :frown:

Reply 13

ChrisRH

Well yeah 589x2 = 1178 =]
Thanks. If the cubes floated just below the surface, so that just the top face of each cube was visible, I assume it would then be 589kgm^3?

Yup

Reply 14

I found the maths sample paper harder than the physics sample papre but the November 2006 Maths papre easier than the November Physics paper. What answers did people get for the novermber maths paper??

Reply 15

My math teacher gave me perfect answers for the sample test

1.3

2 landa<1 landa>9

3. either show that gradients give product of -1 or use pythag then area is 15

4. sin^2 is always positive and slightly sleeper
ii) tanx=sinx/cosx therfore sinx=cosxtanx between 0 and pi/2 0<cos x<1 therfore sinx < tanx
iii)@=theta cos^4@=(cos^2@)^2
ect expand out sub in
1/8(3+4cos2@+cos4@)

5.i)X=4
ii)x=root 2
iii)x=1

6)64.3845 to 4dp

7. sn=h/2(1+1/3^n-1)
distance = h/2(3+5/3^n)

8.5/36 and 15/36 or 5/12

9/ all positive v with point at 0,1
area=4

10.5th term = a-4d/4=0

11. greatest y=66 least y=-15

would be intersted to see waht people got for the november paper.

Reply 16

.:Emmy:.

My math teacher gave me perfect answers for the sample test

7. sn=h/2(1+1/3^n-1)
distance = h/2(3+5/3^n)

Probably a dangerous person to argue against but here goes... :p:

The total distance traveled by the ball to me strikes me as being sum to infinity, not sum to n. Plus sum to infinity gives a much simpler answer.

Un = ar^{n-1}

a = h/3

(original bounce has to be ignored)

r = 1/3

S\infty = \frac{a}{1-r}

S\infty = \frac{\frac{h}{3}}{1-\frac{1}{3}}

S\infty = \frac{\frac{h}{3}}{\frac{2}{3}}

S\infty = \frac{h}{2}

However, since the ball bounces up and down the sum to infinity must be multiplied by two, giving you a value of h. Then finally you can take into account the start distance of h by adding them together, giving a final answer of 2h. :smile:

Would be very interested in hearing what your maths teacher says, knowing maths teachers he'll probably be right :p:

Reply 17

Knowing my maths teacher he will probably try to prove you wrong whether you are right or not.

Her are the answers i got to the November 2006 one. Most will be wrong.

1. i) 413
ii)0.0015151 so to 1sf 0.002

2.-10

3.x= 2
x=2/3

4. could some one tell me how to do this question

5.all positive
ii) 2 asemtopes ((i think this is wrong))

6. i think this is sooo sooo wrong so i am not posting it.

7.i)1/36
ii)1/6
iii)25/36

8. rates of change i love them!!! dr/dt = 10/4pir^2 with 3pir^2 being surface area
hence the answer being 1/10

9. unsure how this works

10. also unsure
ii)-2

11.unsure

12 aslo unsure

tips on how to solve these very apreciated.

Reply 18

actually I think morgan is right the answer is 2h

Nov 06

1 i) 4013
ii) ??

2) -10

3 x=2
x=3

4 12

5 yep all positive and two asymptotes

6 0.5 and 1.5

7 i) 1/216 (1/6*1/6*1/6(becase there are three dice)
ii) 1/36
iii) 25/216

then i pretty much didnt do the rest

Reply 19