Well imagine that the selectors wish to indicate to the players which have been picked to play.
Suppose that you have 8 boxes labelled A to H and 8 cards 2 of 1, 2 of 2, 2 of 3 and 2 of 4 What the
selectors have to do is place the 8 cards in the eight boxes and they can do this in any order.
This can be done in 8! / 2^4 ways = 2520 ways, many more than the 107 you thought possible I shall
give you the first 6.
A B C D E F G H 1 1 2 2 3 3 4 4 1 1 2 2 3 4 3 4 1 1 2 2 3 4 4 3 1 1 2 2 4 3 3 4 1 1 2 2 4 3 4 3 1 1
2 2 4 4 3 3
As to your second question You can pick a number 1 seed from one of 8 groups Then the 2nd seed from
one of the remaining 7 groups 3rd seed from one of the remaining 6 groups 4th seed from one of the
remaining 5 groups.
So you can make your choice in 8x7x6x5 different ways = 1680 ways
Joe Bradley
Michael Darling wrote in message ...
[q1]>Could someone help me with this:[/q1]
[q1]>[/q1]
[q1]>There are 32 selections seeded from 1 to 4 into 8 groups (i.e. group A[/q1]
[q1]>[/q1]
[q1]>has a 1, 2, 3 & 4 seed, group 2 has an 1, 2, 3 & 4 seed etc). I have to[/q1]
pick
[q1]>8 of[/q1]
[q1]>[/q1]
[q1]> these, 1 (and only 1) from each group and can only pick 2 seed 1s, 2 seed 2s, 2 seed 3s and 2[/q1]
[q1]> seed 4s.[/q1]
[q1]>[/q1]
[q1]>This may help explain it better:[/q1]
[q1]>[/q1]
[q1]> One valid selection might be A1, B2, C3, D4, E1, F2, G3, H4 while another is A4, B3, C2, D1, E4,[/q1]
[q1]> F3, G2, H1[/q1]
[q1]>[/q1]
[q1]>However A1 and A2 cannot be selected together nor A1, B1 and C1.[/q1]
[q1]>[/q1]
[q1]>The whole list is:[/q1]
[q1]>[/q1]
[q1]>G S[/q1]
[q1]>[/q1]
[q1]>-- ---[/q1]
[q1]>[/q1]
[q1]>A 1[/q1]
[q1]>[/q1]
[q1]>A 2[/q1]
[q1]>[/q1]
[q1]>A 3[/q1]
[q1]>[/q1]
[q1]>A 4[/q1]
[q1]>[/q1]
[q1]>B 1[/q1]
[q1]>[/q1]
[q1]>B 2[/q1]
[q1]>[/q1]
[q1]>B 3[/q1]
[q1]>[/q1]
[q1]>B 4[/q1]
[q1]>[/q1]
[q1]>C 1[/q1]
[q1]>[/q1]
[q1]>C 2[/q1]
[q1]>[/q1]
[q1]>C 3[/q1]
[q1]>[/q1]
[q1]>C 4[/q1]
[q1]>[/q1]
[q1]>D 1[/q1]
[q1]>[/q1]
[q1]>D 2[/q1]
[q1]>[/q1]
[q1]>D 3[/q1]
[q1]>[/q1]
[q1]>D 4[/q1]
[q1]>[/q1]
[q1]>E 1[/q1]
[q1]>[/q1]
[q1]>E 2[/q1]
[q1]>[/q1]
[q1]>E 3[/q1]
[q1]>[/q1]
[q1]>E 4[/q1]
[q1]>[/q1]
[q1]>F 1[/q1]
[q1]>[/q1]
[q1]>F 2[/q1]
[q1]>[/q1]
[q1]>F 3[/q1]
[q1]>[/q1]
[q1]>F 4[/q1]
[q1]>[/q1]
[q1]>G 1[/q1]
[q1]>[/q1]
[q1]>G 2[/q1]
[q1]>[/q1]
[q1]>G 3[/q1]
[q1]>[/q1]
[q1]>G 4[/q1]
[q1]>[/q1]
[q1]>H 1[/q1]
[q1]>[/q1]
[q1]>H 2[/q1]
[q1]>[/q1]
[q1]>H 3[/q1]
[q1]>[/q1]
[q1]>H 4[/q1]
[q1]>[/q1]
[q1]>[/q1]
[q1]>[/q1]
[q1]>I am trying to find out how many unique combinations there are from this.[/q1]
[q1]>[/q1]
[q1]>It would be nice to know how you work it out too.[/q1]
[q1]>[/q1]
[q1]>I think that due to the restrictions there are only 107 possible combinations, but I could easily[/q1]
[q1]>be well wrong as my math is not that[/q1]
great.
[q1]>[/q1]
[q1]>Also I am interested to know how changing the rules to only having to pick four selections where I[/q1]
[q1]>must pick 1 of each seed but can pick the four from any group as long as I only pick at most 1 from[/q1]
[q1]>each group would effect the possible combinations, I imagine this will increase the possible[/q1]
[q1]>selections by a lot.[/q1]
[q1]>[/q1]
[q1]>Thank you for getting this far[/q1]
[q1]>[/q1]
[q1]>[/q1]