i dont even know where to start with this question
A sketch should help. Youre given the radius is r and the question wants you to work the question through with r being a variable. So if it touches both axes, what would be the centre, ...
A sketch should help. Youre given the radius is r and the question wants you to work the question through with r being a variable. So if it touches both axes, what would be the centre, ...
would the equation be (x+r)^2+(x+y)^2=r^2 and then make that equal to 0 and make 2x+y=12 equal to 0 and then equate them..?
would the equation be (x+r)^2+(x+y)^2=r^2 and then make that equal to 0 and make 2x+y=12 equal to 0 and then equate them..?
Right idea for the circle, but check the centre.
You solve the line and circle simultaneously which as the circle is nonlinear/quadratic its easier to do by substitution. As you want to end up with a quadratic in x, you substitute ...
You solve the line and circle simultaneously which as the circle is nonlinear/quadratic its easier to do by substitution. As you want to end up with a quadratic in x, you substitute ...
ohhhh so it would be (x-r)^2+(y-r)^2=r^2 i was thinking about quadrant 2 and still did it wrong 😭
Yup. If you know the centre so (r,r) here, you just check your circle equation gives 0^2 + 0^2 = ... as the centre must be a zero distance from the centre. Hence you negate the actual sign of the centre in circle equation.
So now follow the simultaneous - substitution advice in a prevoius post.