Edexcel GCSE maths, give each other questions to do.

You purposely put probably one of the hardest FM questions in order to taunt people about their abilities on an online forum. Pretty pathetic lmao

but I do not understand , u rooted the (2^10) to get 2^5, but would you not have to root the 2 as well.

Lol why does he charge for solutions, all of those questions are past paper questions and you can find them on the internet :/
There's also a lot of videos of people going through exam papers, including june 2009 and 2010, which some of the questions are from.

someone give me a rly hard question im bored

heres something

thank you so much!!!

lol ok well it's a starter, then in that case, try dis http://prntscr.com/b6fzjk, gonna replace my first link with this one actually.

no that's not how this works

$\left(2^2\right)^2= 2^4$

$2^2=2^2[br][br][br]2^2 \not = \sqrt {2^2}$

Initially it looked difficult but I put my head into it and it was pretty easy! Not sure if it is correct though but my final answer I suppose proves it.

could you say the the square root of 2¹⁰ is the same as 2^10x1/2 which is 2⁵

ikr idk why so many people are saying it's so hard

ahhh 1600, thought it said 1000, very hard to read , pic was blurry for me sry.

ok
so

$\left(\dfrac{2^{-3x}}{2^{-2}}\right)^2=2^{10}$

$\dfrac{2^{-3x}}{2^{-2}}=2^5$

$2^{-3x}=2^3$

$\dfrac{1}{2^{3x}}=2^3$

$\dfrac{1}{2^3}=2^{3x}$

$\dfrac{1}{2^3}=\left(2^x\right)^3$

let $2^x$ = y

$\dfrac{1}{8}=y^3$

$\dfrac{1}{2}=y$

$2^x=\dfrac{1}{2}$

x=-1

I still don't understand how you got from:

$\left(\dfrac{2^{-3x}}{2^{-2}}\right)^2=2^{10}$

to

$\dfrac{2^{-3x}}{2^{-2}}=2^5$

Like the other guy said, why don't you square root 10 but instead divide it by 2?

I still don't understand how you got from:

$\left(\dfrac{2^{-3x}}{2^{-2}}\right)^2=2^{10}$

to

$\dfrac{2^{-3x}}{2^{-2}}=2^5$

Like the other guy said, why don't you square root 10 but instead divide it by 2?

i'm not quite sure what you want to say? can you explain it to me in some sort of calculation?

to get from step 1 to step 2 you square root both sides