The Student Room Group

C1 question - please help!!!

Hi can someone explain how to do this, without using factor theorum (using differentiation)

Find the other point where y=9x-6 and y=3x^3+x^2-2x+1 meet. They also meet at (1,3)

The answer is (-7/3, -27)

Thanks
Reply 1
Use simultaneous equation for this.

EDIT: Whoops.
if

y= f(x) and y=f(x)

then y = y

put them equal to each other and factorise, then use this x value to find the y.
Reply 3
Original post by hannah1994
Hi can someone explain how to do this, without using factor theorum (using differentiation)

Find the other point where y=9x-6 and y=3x^3+x^2-2x+1 meet. They also meet at (1,3)

The answer is (-7/3, -27)

Thanks


Why would you use differentiation?
Reply 4
Hey how would you do part B and C?
a) Calculate the sum of all the even numbers from 2 to 100 inclusive, 2 + 4 + 6 + ...... + 100
(b) In the arithmetic series
k + 2k + 3k + ...... + 100 k is a positive integer and k is a factor of 100.
(i) Find, in terms of k, an expression for the number of terms in this series.
(ii) Show that the sum of this series is
50 + 5000/k
Reply 5
Original post by Jam'
Why would you use differentiation?


Because its C1, and factor theroum is in C2 and its a differentiation question. I think its something to do with the gradient of the tangent = dy/dx, but i don't know how to do it
Reply 6
Is it the other intersection or that the gradients are parallel?
Reply 7
Original post by hannah1994
Because its C1, and factor theroum is in C2 and its a differentiation question. I think its something to do with the gradient of the tangent = dy/dx, but i don't know how to do it


I do C1, pretty sure factor thereom is in it!
Reply 8
Original post by DrFantastic
I do C1, pretty sure factor thereom is in it!


hmm well I do OCR and its definately not cos we've just started C2 and its the first thing we did
Reply 9
Original post by angelpav
Hey how would you do part B and C?
a) Calculate the sum of all the even numbers from 2 to 100 inclusive, 2 + 4 + 6 + ...... + 100
(b) In the arithmetic series
k + 2k + 3k + ...... + 100 k is a positive integer and k is a factor of 100.
(i) Find, in terms of k, an expression for the number of terms in this series.
(ii) Show that the sum of this series is
50 + 5000/k


a) a=2 d=2 n=(98-2)/2 + 1
substitute in n/2 (2a+(n-1)d)

b) i) a=K d=k
n=(100-k)/k +1
ii) substitute in the formula
n/2 (2a+(n-1)d)
Reply 10
Original post by baggyyo

Original post by baggyyo
a) a=2 d=2 n=(98-2)/2 + 1
substitute in n/2 (2a+(n-1)d)

b) i) a=K d=k
n=(100-k)/k +1
ii) substitute in the formula
n/2 (2a+(n-1)d)


Thank You
Reply 11
solve 8x(1+x^2)=0
Reply 12
Original post by angelpav
solve 8x(1+x^2)=0


8x(1+x2)=0 8x(1+x^2)=0

Now you get two equation, one is,
8x=0 8x = 0 , this equation gives you the real solutions.

The other equation, is,
1+x2=0 1+x^2 = 0, this equation gives you the imaginary solutions. If you haven't done FP1 than you will probably not know what are imaginary solutions, hence only write the answer given by the first equation. Say that the second equation has no real solutions because you can't take the square root of a negative number.

Quick Reply

Latest

Trending

Trending