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mechanics help!

What do you do for the second part of part i) Please help
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Original post by h26
What do you do for the second part of part i) Please help
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How do you find the equation of a straight line?
Reply 2
Original post by tiny hobbit
How do you find the equation of a straight line?

why would you find the equation of the straight linr- the gradient doesn't give the speed could you please lemme know?
Original post by h26
why would you find the equation of the straight linr- the gradient doesn't give the speed could you please lemme know?


Part (i) - did you get an answer?

part (ii) you need to find the equation for the accel in terms of t ... y = mx + c with c = 0 as the line passes through the origin.
Reply 4
Original post by Muttley79
Part (i) - did you get an answer?

part (ii) you need to find the equation for the accel in terms of t ... y = mx + c with c = 0 as the line passes through the origin.

Ah sorry I am stuck on the second part of i) Could you please help with that?
Original post by h26
Ah sorry I am stuck on the second part of i) Could you please help with that?


Yes -what does the area under the graph represent?
Original post by h26
why would you find the equation of the straight linr- the gradient doesn't give the speed could you please lemme know?


Apologies, I just read second part and thought you meant part ii.
Reply 7
Original post by Muttley79
Yes -what does the area under the graph represent?

But can you not do (v-u)/t =a as the acceleration is the change in velocity so since u=0 and t=4 and a=8 I did (v-0)/4 =8 so v=32 but the answer is 16 Could you please let me know where I went wrong?
Original post by h26
But can you not do (v-u)/t =a as the acceleration is the change in velocity so since u=0 and t=4 and a=8 I did (v-0)/4 =8 so v=32 but the answer is 16 Could you please let me know where I went wrong?


Acceleration is not constant and it needs to be to use that equation.

Do you know the answer to the question I posed?
Reply 9
Original post by Muttley79
Acceleration is not constant and it needs to be to use that equation.

Do you know the answer to the question I posed?

does it represent velocity? or velocity change actually I am not sure could you please let me know?
Original post by h26
does it represent velocity? or velocity change actually I am not sure could you please let me know?


Here it will be velocity and give you what you are looking for.

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