A level maths question help
How would you work out the equation of the quadratic curve and is there more than one way to work it out?
It seems I've completely forgotten XD
Btw this is from edexcel a level october 2020 paper 1
It seems I've completely forgotten XD
Btw this is from edexcel a level october 2020 paper 1
(edited 10 months ago)
Couple ways:
1, The most direct way, if you know the "vertex form" of a quadratic (i.e. the "completed square" form), then we have
y = A(x-"x-coordinate of vertex")^2 + "y-coordinate of vertex".
You just need to find A such that it passes through (0,25).
2, If you forget about it, you can just write it out in general form y = ax^2 + bx + c, and using three clues to find a, b, c:
(a) it passes through (0,25)
(b) it passes through (-2,13)
(c) (-2,13) also happen to be a minimum, i.e. a stationary point.
1, The most direct way, if you know the "vertex form" of a quadratic (i.e. the "completed square" form), then we have
y = A(x-"x-coordinate of vertex")^2 + "y-coordinate of vertex".
You just need to find A such that it passes through (0,25).
2, If you forget about it, you can just write it out in general form y = ax^2 + bx + c, and using three clues to find a, b, c:
(a) it passes through (0,25)
(b) it passes through (-2,13)
(c) (-2,13) also happen to be a minimum, i.e. a stationary point.
(edited 10 months ago)
Original post by tonyiptony
Couple ways:
1, The most direct way, if you know the "vertex form" of a quadratic (i.e. the "completed square" form), then we have
y = A(x-"x-coordinate of vertex")^2 + "y-coordinate of vertex".
You just need to find A such that it passes through (0,25).
2, If you forget about it, you can just write it out in general form y = ax^2 + bx + c, and using three clues to find a, b, c:
(a) it passes through (0,25)
(b) it passes through (-2,13)
(c) (-2,13) also happen to be a minimum, i.e. a stationary point.
1, The most direct way, if you know the "vertex form" of a quadratic (i.e. the "completed square" form), then we have
y = A(x-"x-coordinate of vertex")^2 + "y-coordinate of vertex".
You just need to find A such that it passes through (0,25).
2, If you forget about it, you can just write it out in general form y = ax^2 + bx + c, and using three clues to find a, b, c:
(a) it passes through (0,25)
(b) it passes through (-2,13)
(c) (-2,13) also happen to be a minimum, i.e. a stationary point.
Thank you! I used the second method and I realised I made some silly mistakes lol
Quick Reply
Related discussions
- GCSE Exam Discussions 2024
- TSR Study Together - STEM vs Humanities!
- I have a lot OF A-level and GCSE Maths and Further Maths resources. Who's Interested?
- A level physics without maths
- What is the syllabus for the futher maths gcse this year?
- maths a level
- Further maths and maths A level help
- maths revision help
- Maths GCSE/A level
- A Level Maths vs IB SL AA Maths
- How should i be revising for maths?
- help !!
- Worried about degree difficulty - Chemistry
- Should I take further maths A level?
- how to go from a grade5/6 in maths to a grade 7 in a month for gcses. please help
- I achieved mostly 9s and some 8s at GCSE
- A Level Maths Checklist
- Is the physics in an Engineering degree much harder than A Level physics?
- Are the CGP books good for these A level subjects?
- aqa foundation maths
Latest
Trending
Last reply 4 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
Trending
Last reply 4 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
