In question 1.. how did u calculate W1? was it from the graph or using the gradient given? i found 0.65N using the gradient method. and 0.45N using graph.. shouldnt they be similar? or did i miscalculated from the graph?

Reply 111

Aimen.

7

Original post by apocolyptic

Any idea what the boundaries will be

something like this:

Reply 112

Aimen.

7

Original post by Propoganda

In question 1.. how did u calculate W1? was it from the graph or using the gradient given? i found 0.65N using the gradient method. and 0.45N using graph.. shouldnt they be similar? or did i miscalculated from the graph?

I did it from graph and it was 0.65 so they were equivalent cuz I matched with k value aswell and both methods gave 0.65 so probably you misread the graph!

Reply 113

Propoganda

what do u think the grade boundary will look like? will they do much scaling?

Reply 114

Sonalucard

Okay. 1st Q: How'd you get the uncertainties? Did you use the graph anyhow? 2nd Q: Well I pretty much know what I got wrong there so whatevs. 3rd Q: .40+1.60=2.00s? 4Q: p=2.65 or sth? theoretical e=? This was so easy compared to the horror that was chemistry. Yet I choked. I feel effing miserable. Need the A too. 4 and 5 it is then, I guess

Reply 115

Clutched

1

Question 1 killed the paper :frown:

other than that its an okay paper
Its the strangest Q1 paper ever

Reply 116

jz157

What did you guys write for the things we had to measure for the question involving the capacitor?

Reply 117

amohsen982

1

In 1st question i multipled the lengtg by the gradient to get the weight got like 1.023 that correct?
And the uncertainity was 0.03
And pecentage was 1.47% correct?
And w2 also used same method and got .65 did what i do was correct

Reply 118

The_Big_E

11

Original post by Aimen.

oops yea it was cx/gradient , I did a mistake up there!

Would this be right as well?

V_2 = \frac{C_x}{C_y}(V_1-V_2)

C_y V_2 = C_x V_1 - C_x V_2

C_x V_2 + C_y V_2 = C_x V_1

V_2 (C_x + C_y) = C_x V_1

V_2 = \frac{C_x}{C_x + C_y} V_1

Graph of

V_2

against

V_1

where

\frac{C_x}{C_x + C_y}

is the gradient.

Reply 119

Zacken

22

Original post by amohsen982

In 1st question i multipled the lengtg by the gradient to get the weight got like 1.023 that correct?
And the uncertainity was 0.03
And pecentage was 1.47% correct?
And w2 also used same method and got .65 did what i do was correct

I think all of that is wrong.

Edexcel International A level (IAL): Physics Unit 6 (WPH06) - 19th May, 2016 - PM

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