If G is a group with operation ∘ then the identity, I is the element in G for which:
I∘g=g∀g∈G
Okay so I just do trial and error? My teacher said for the tables to see which one where the row and coloumn matched up but it doesn't seem to work in this case
Okay so I just do trial and error? My teacher said for the tables to see which one where the row and coloumn matched up but it doesn't seem to work in this case
Yeah for small groups just draw the group table and see which element follows that rule.
If it doesn't work, you've made an arithmetic error.