Standard Grade Maths !
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Original post by mrsnicket
Oh crap! I just got x= 11.5 and x= 180 - 11.5= 168.5 
I think that was correct since the answer plugged into inverse sine wasn't a negative, which meant it was x and 180-x
Original post by michaelroy
Hey can anyone upload the paper? I'd be happy to solve and post the solutions?
few of us asking that - someone pm-ed me a link but it doesn't work
Original post by posterpreviouslyknownascoss:D
few of us asking that - someone pm-ed me a link but it doesn't work
Hi, i have the papers on pdf, ill upload them now and send a link.
Original post by mrsnicket
Oh crap! I just got x= 11.5 and x= 180 - 11.5= 168.5
Unless I'm missing something important (which I'm not), that's correct.
All = x = 11.5
Sin = 180 - x = 168.5
If you aren't sure about a question like that just draw an approximate graph of whatever function it is (cos, sin, tan) and find x on it.
Original post by AtomSmasher
Unless I'm missing something important (which I'm not), that's correct.
All = x = 11.5
Sin = 180 - x = 168.5
If you aren't sure about a question like that just draw an approximate graph of whatever function it is (cos, sin, tan) and find x on it.
All = x = 11.5
Sin = 180 - x = 168.5
If you aren't sure about a question like that just draw an approximate graph of whatever function it is (cos, sin, tan) and find x on it.
Yass! I could do these questions easily in pps, so I had a hunch I'd done something right in the exam. Thanks 
Original post by weejackig
any1 else use simultaneous equations in paper 1 to calculate the coordinates of P
Yup! P: (4,5)
Original post by mrsnicket
Yup! P: (4,5)
thanks I got the same
did anyone get 200/x(x+5) for the difference in the driving question
Original post by scottishstudent462
did anyone get 200/x(x+5) for the difference in the driving question
I got 200/xsquared + 5x so yes
Original post by scottishstudent462
did anyone get 200/x(x+5) for the difference in the driving question
No.
I found paper 1 quite challenging but paper 2 was really easy. I'll post all my answers to Paper 1 (not that they are necessarily correct 
)
1) 2.37
2) 6x^3 -x^2 +13x -10
3) m = (Lk)^2
4) x = 2root11
5) Yes, scoring rate improved as he scores 1 more goal for every 25 attempts
6a) x = 2
b) x=2, y=9 (2,9)
7) Used quadratic formula, simplified it, simplified the root12 as a surd, then factorised using 2, allowing me to cancel down to the answer
8) (4,5)
9a) 40 / x
b) 40 / (x+5)
c) 200 / x(x+5)
10a) 64
b) n = -2
11a) 110
b) (0.5n)(0.5n+1) = 0.25n^2 + 0.5n
c) 2530
I forgot to take paper 2 questions out of the exam room so I can't post my answers for that
)1) 2.37
2) 6x^3 -x^2 +13x -10
3) m = (Lk)^2
4) x = 2root11
5) Yes, scoring rate improved as he scores 1 more goal for every 25 attempts
6a) x = 2
b) x=2, y=9 (2,9)
7) Used quadratic formula, simplified it, simplified the root12 as a surd, then factorised using 2, allowing me to cancel down to the answer
8) (4,5)
9a) 40 / x
b) 40 / (x+5)
c) 200 / x(x+5)
10a) 64
b) n = -2
11a) 110
b) (0.5n)(0.5n+1) = 0.25n^2 + 0.5n
c) 2530
I forgot to take paper 2 questions out of the exam room so I can't post my answers for that
Original post by andrewmc96
I found paper 1 quite challenging but paper 2 was really easy. I'll post all my answers to Paper 1 (not that they are necessarily correct )
1) 2.37
2) 6x^3 -x^2 +13x -10
3) m = (Lk)^2
4) x = 2root11
5) Yes, scoring rate improved as he scores 1 more goal for every 25 attempts
6a) x = 2
b) x=2, y=9 (2,9)
7) Used quadratic formula, simplified it, simplified the root12 as a surd, then factorised using 2, allowing me to cancel down to the answer
8) (4,5)
9a) 40 / x
b) 40 / (x+5)
c) 200 / x(x+5)
10a) 64
b) n = -2
11a) 110
b) (0.5n)(0.5n+1) = 0.25n^2 + 0.5n
c) 2530
I forgot to take paper 2 questions out of the exam room so I can't post my answers for that
)1) 2.37
2) 6x^3 -x^2 +13x -10
3) m = (Lk)^2
4) x = 2root11
5) Yes, scoring rate improved as he scores 1 more goal for every 25 attempts
6a) x = 2
b) x=2, y=9 (2,9)
7) Used quadratic formula, simplified it, simplified the root12 as a surd, then factorised using 2, allowing me to cancel down to the answer
8) (4,5)
9a) 40 / x
b) 40 / (x+5)
c) 200 / x(x+5)
10a) 64
b) n = -2
11a) 110
b) (0.5n)(0.5n+1) = 0.25n^2 + 0.5n
c) 2530
I forgot to take paper 2 questions out of the exam room so I can't post my answers for that
Dammit.
Original post by andrewmc96
I found paper 1 quite challenging but paper 2 was really easy. I'll post all my answers to Paper 1 (not that they are necessarily correct )
1) 2.37
2) 6x^3 -x^2 +13x -10
3) m = (Lk)^2
4) x = 2root11
5) Yes, scoring rate improved as he scores 1 more goal for every 25 attempts
6a) x = 2
b) x=2, y=9 (2,9)
7) Used quadratic formula, simplified it, simplified the root12 as a surd, then factorised using 2, allowing me to cancel down to the answer
8) (4,5)
9a) 40 / x
b) 40 / (x+5)
c) 200 / x(x+5)
10a) 64
b) n = -2
11a) 110
b) (0.5n)(0.5n+1) = 0.25n^2 + 0.5n
c) 2530
I forgot to take paper 2 questions out of the exam room so I can't post my answers for that
)1) 2.37
2) 6x^3 -x^2 +13x -10
3) m = (Lk)^2
4) x = 2root11
5) Yes, scoring rate improved as he scores 1 more goal for every 25 attempts
6a) x = 2
b) x=2, y=9 (2,9)
7) Used quadratic formula, simplified it, simplified the root12 as a surd, then factorised using 2, allowing me to cancel down to the answer
8) (4,5)
9a) 40 / x
b) 40 / (x+5)
c) 200 / x(x+5)
10a) 64
b) n = -2
11a) 110
b) (0.5n)(0.5n+1) = 0.25n^2 + 0.5n
c) 2530
I forgot to take paper 2 questions out of the exam room so I can't post my answers for that
Good post - I'm pretty sure these are all the correct answers
http://www37.zippyshare.com/v/23037676/file.html
Both papers, scanned by someone else, I just put them both together and fixed some slant issues and removed the writing which had also been scanned.
Both papers, scanned by someone else, I just put them both together and fixed some slant issues and removed the writing which had also been scanned.
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