AQA Core 4 Exam Discussion 14/06/2012 !Poll, paper and unofficial MS (first post)!

Dont understand the markscheme can someone helpppp!!

Question 8 jun 07..When you integrate

doesnt it get divided by half(or multiplied by 2)

Reply 150

Hi guys.. I need help! I know this sounds like easy stuff.. but this has always got to me!
say '•' is theta, as I don't have that symbol ha

right so Sin2• , is different to 2Sin•

but if I was doing (Sin2•)/(sin•) what would it be?

:frown:

Reply 151

again.. so if cos•= 3/5
what would cos2• equal??
as it wouldn't be 2 x 3/5.. as that would be 2cos•

very confused!!

Reply 152

Original post by lara_ox

Dont understand the markscheme can someone helpppp!!

Question 8 jun 07..When you integrate

doesnt it get divided by half(or multiplied by 2)

can't see the picture very well, is that 2/pie squared ??

Reply 153

Original post by KTucker93

Hi guys.. I need help! I know this sounds like easy stuff.. but this has always got to me!
say '•' is theta, as I don't have that symbol ha

right so Sin2• , is different to 2Sin•

but if I was doing (Sin2•)/(sin•) what would it be?

:frown:

You cant simplify that any further just leave it in that form

Reply 154

Original post by KTucker93

can't see the picture very well, is that 2/pie squared ??

hmm nope theres no pi in it all all....if you click on the picture doesnt it get bigger.

heres the link to the markscheme question 8a http://store.aqa.org.uk/qual/gceasa/qp-ms/AQA-MPC4-W-MS-JUN07.PDF

(edited 11 years ago)

Reply 155

I'm on my phone so clicking on pic wouldn't work. i'll look at mark scheme now.
and I can't leave it in that form :s-smilie:

it's question 6(a)(ii) on jan 2010 I'm doing

Reply 156

Original post by KTucker93

I'm on my phone so clicking on pic wouldn't work. i'll look at mark scheme now.
and I can't leave it in that form :s-smilie:

it's question 6(a)(ii) on jan 2010 I'm doing

Ok sin2• is equal to 2sin•cos•
= 2 x sin• x cos •
= 2 x (4/5) x (3/5)
=24/25

Reply 157

Oromis263

2

Original post by KTucker93

Hi guys.. I need help! I know this sounds like easy stuff.. but this has always got to me!
say '•' is theta, as I don't have that symbol ha

right so Sin2• , is different to 2Sin•

but if I was doing (Sin2•)/(sin•) what would it be?

:frown:

\dfrac {\sin 2x} {\sin x}=\dfrac {2\cos x\sin x} {\sin x}

This part was done using the double angle formulae, which you really ought to be familiar with.

=2\cos x

Reply 158

hash007

15

With part 8b) from the Jan 12 paper, the vectors part. The paper has been posted is you scroll up.

I've found the value for lambda which is 3/2, then I have to find the co-ordinates for D which I don't know how to.

Reply 159