The Edexcel C3 (14/06/12 - AM) Revision Thread
Maths exam discussion - share revision tips in preparation for GCSE, A Level and other maths exams and discuss how they went afterwards.
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Re: The Edexcel C3 (14/06/12 - AM) Revision ThreadJust try to achieve your best!!(Original post by ak395)
Ok... thnx for that... i do like differentiation but i just looked at the book and all the weird symbols are scaring me but i guess ill take it as it goes... i have 93 average ums for my as level and i think *hope* i did well in m1 so i can afford to get slightly lower... ok i know u r probs not very interested but this is my form of calming myself down
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Re: The Edexcel C3 (14/06/12 - AM) Revision ThreadTrigonometry and Differentiation are both very 'big' chapters so we must expect 'big' questions involving these two chapters.(Original post by otrivine)
my teacher thinks that this would be a hard paper ? and he said there could be a big question like differentiation/trig
when they c3 will be difficult like how cause all the papers seem to look same? which paper was the hardest till now? -
Re: The Edexcel C3 (14/06/12 - AM) Revision Threadbut like which paper was the most difficult till now?(Original post by M Kh)
Trigonometry and Differentiation are both very 'big' chapters so we must expect 'big' questions involving these two chapters. -
Re: The Edexcel C3 (14/06/12 - AM) Revision Thread(Original post by Souriretoujours)
likewise
its really beginning to stress me out especially after january's performance lol x

S2 didnt go too well either...
I need an average of 83UMS on S2 C3 C4 -
Re: The Edexcel C3 (14/06/12 - AM) Revision Thread(Original post by Souriretoujours)
Yeah I repeated M1 in early may hoping to have got at least 70 UMS. S1 went really well so hoping for85-90 UMS which would leave me needing about 75 in C3 and C4
but I'm terrible at both of them so
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Re: The Edexcel C3 (14/06/12 - AM) Revision ThreadI am not sure really - it just depends on you. Maybe check the grade boundaries to see which was the hardest paper?(Original post by otrivine)
but like which paper was the most difficult till now? -
Re: The Edexcel C3 (14/06/12 - AM) Revision Threadjan 11 was quite hard imo...and jan 10.(Original post by M Kh)
I am not sure really - it just depends on you. Maybe check the grade boundaries to see which was the hardest paper?Last edited by -James-; 31-05-2012 at 15:57. -
Re: The Edexcel C3 (14/06/12 - AM) Revision Threadah ok thank you(Original post by grazie)
For part a), given that

Then

And the cosine of an angle is the same as the sin(
- angle). So...

Taking arcsin on both sides

For part b), you're given arccos x in part a) and then worked out arcsin x. So


I think the problem with this question is that few (or perhaps none) examples are given in the textbook.
Yeah the problem was that i had never come across a problem like that before -
Re: The Edexcel C3 (14/06/12 - AM) Revision ThreadYea, good luck revising.(Original post by -James-)
jan 11 was quite hard imo...and jan 10. -
Re: The Edexcel C3 (14/06/12 - AM) Revision ThreadI have no idea how to sketch y = |x+4| + |x-1| tbh, that's mad hard.(Original post by emmaaa88)
I'm confused by this question in my textbook, I know it's just modulus but any help would be appreciated!
Sketch this graph:
y = |x+4| + |x-1|
Also does anyone have any useful ways of remembering the vector transformations because I am not good at those!
But if you're asking about graph transformations (I assumed that's what you meant by vector transformations?), then I remember how to do graph transformations using this:
If y=f(x) and 'a' is a number, then perform the following actions to the graph:
y = af(x) -----> Multiply all y-coordinates by 'a'
y = f(x) + a -----> Add 'a' to all y-coordinates
y = f(ax) -----> Multiply all x-coordinates by '1/a'
y = f(x+a) -----> SUBTRACT 'a' from all x-coordinates.
Also, for me, I do graph transformations step-by-step and do the things closest to the 'x' first / using BIDMAS, so, if it gives you y = f(x) and says draw the graph of:
y = 2f(3x) - 5
I draw the graph of y=f(3x) first, by multiplying all x-coordinates by '1/3',
then I draw the graph of y = 2f(3x) by multiplying all y-coordinates by '2',
then I draw the final graph of y = 2f(3x) - 5 by subtracting '5' from all y-coordinates, which is the graph they're looking for.
Hope that helps a bitLast edited by House3; 31-05-2012 at 16:49. -
Re: The Edexcel C3 (14/06/12 - AM) Revision Thread
anyone wanna explain the reasoning why this (the last part at the bottom) is wrong?

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Sorry about the crappy quality of the image lol -
Re: The Edexcel C3 (14/06/12 - AM) Revision ThreadWhen you apply a function to an equation, it must be applied to the whole of each individual side, as you would when dividing each side of an equation or multiplying each side of an equation. Hence you can't apply logarithms like that.(Original post by arnab)
anyone wanna explain the reasoning why this (the last part at the bottom) is wrong?

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Sorry about the crappy quality of the image lol
i.e. The second line should read ln(e^x + 3e^(-x)) = ln(4) which you can't do anything with.
You can solve this like so:
e^x + 3e^(-x) = 4
Multiply through by e^x
e^2x + 3 = 4e^x
e^2x - 4e^x + 3 = 0
Solve as you would a quadratic
(e^x - 1)(e^x - 3) = 0
e^x = 1, 3
x = ln(1), ln(3)
x = 0, 1.0986...Last edited by Dark Lord of Mordor; 31-05-2012 at 21:06. -
Re: The Edexcel C3 (14/06/12 - AM) Revision ThreadI thought compared to Jun 11 and Jan 12.(Original post by M Kh)
Yea, good luck revising.
did you find them easy?
its really beginning to stress me out especially after january's performance lol x

