Mocks- less than a week away and need to for mahts cram to get good marks

Anyone? I am not sure what to do over here

if you only have 4-5 hours I suggest 2 past papers + looking over the mark scheme and the remaining time learning off information such as indice rules, quadratic formula, sequences and series work and the calculus stuff

Okay thank you; I have been looking at the exam practice section of the book but it seems much more complex than the exams
I was also wondering whether you could help me with this question: (2root2/root3-1) - (2root3/root2 +1) which is from the exam practice; it wants the answer in terms of proot6+qroot3 + rroot2
I tried rationalising but it wouldn't work

youll notice the format of exam questions is slightly different to the textbook questions, so you will have to get used to that

your question is $\displaystyle \frac{2\sqrt{2}}{\sqrt{3}-1} - \frac{2\sqrt{3}}{\sqrt{2}+1}$? (just to make sure im helping you with the right one)

Edit: rationalizing definitely works, is it possible for you to post your workings?

Yes, I know but I have also noticed that the exams tend to be easier than textbook which is odd.
Yes, that's the question; I multiplied the numerator of the surd on the left by its denominator and then and I did the same for the surd on the right with its own denominator

sorry i was out

thats great that you find that the textbook questions are clearly great prep for the exams then

So you done $\displaystyle \frac{2\sqrt{2}}{\sqrt{3}-1} \cdot \frac{\sqrt{3}+1}{\sqrt{3}+1} - \frac{2\sqrt{3}}{\sqrt{2}+1} \cdot \frac{\sqrt{2}-1}{\sqrt{2}-1}$


and ended up with; $\displaystyle \frac{2\sqrt{6} + 2\sqrt{2}}{2}-\frac{2\sqrt{6}-2\sqrt{3}}{1}$

are we in agreement so far?

Yes, I suppose so!
Yes, that's what I did