I'm really worried now, I was resitting it this june because I got a C in wave properties/ practical module last year, and i forgot to put the frigging gradient as negative ****!
I say revise the wave properties well because it is weighted more than the practical.
its because you are taking the log of it... its not voltage anymore. remember when you square something (e.g. distance) it becomes m2... the unit changes. i think its like that. ln V probably does have a unit, its just we're never thought what the unit is. thats my underesting...
EDIT: Actually I think it has something to do with the fact that powers dont have a unit. hmm...
its because you are taking the log of it... its not voltage anymore. remember when you square something (e.g. distance) it becomes m2... the unit changes. i think its like that. ln V probably does have a unit, its just we're never thought what the unit is. thats my underesting...
hmm... I'll ask my teacher. I was writing down the unit, volts, in th exam. But then my teacher told another guy it doesn't have units, I rushed to rub it out :P
hmm... I'll ask my teacher. I was writing down the unit, volts, in th exam. But then my teacher told another guy it doesn't have units, I rushed to rub it out :P
Your teacher can say bye bye to their job if that gets out.
i didnt really understand the 50% light intensity..can someone help me...how to work this out, it was really bugging me, because my thickness ended being something like 5mm and i know thats not right. im gutted because i think i forgot the minus on the gradient, dammit easy marks down the bin!!!
This 1 was tricky... i couldnt do the maths on it. my original reading was 101.1mV so i found 50% which was 50.55mV. then i went back to the light detector and kept addding glass slides untill the voltage dropped to 50.55mV, this was 18 slides, 1 slide was 1.56mm....so 18x1.56 is 28.08mm of slides. thats how i got it!!
What was the answer to the micrometer percentage uncertainty one? Was it around 1% or 10%? I put 10% myself.
(Also it was slightly embarrassing to see that despite being physicists for 7 years in a fairly good grammar school, very few of us were actually able to use or read correctly a micrometer)
its because you are taking the log of it... its not voltage anymore. remember when you square something (e.g. distance) it becomes m2... the unit changes. i think its like that. ln V probably does have a unit, its just we're never thought what the unit is. thats my underesting...
EDIT: Actually I think it has something to do with the fact that powers dont have a unit. hmm...
I thought that logs didn't have units? So whatever unit a quantity may have - when you log it, it becomes unitless.
fblade
hmm... I'll ask my teacher. I was writing down the unit, volts, in th exam. But then my teacher told another guy it doesn't have units, I rushed to rub it out :P
(Also it was slightly embarrassing to see that despite being physicists for 7 years in a fairly good grammar school, very few of us were actually able to use or read correctly a micrometer)
I measured the glass slide with my ruler, and then tried to interpret the micrometer so that my reading from it would be close to my estimate.
It certainly is. Any teacher who helps students in an exam or breaks exam security would face disciplinary action at the least and could lose their teacher registration so they'd never work in teaching again , at the most. And yes, teachers do this and get caught every year. The pressure to get good results makes folk do crazy things.
if you look at the question it asked to take ln of (V/mV) or something along those lines....thats because the voltage (i.e the value of V) has the value and an associated unit namely mV so the mV's cancel and you're left with a pure number.
e.g. if you found your voltage as 200 mV (say) you can't do ln 200mV..so you do ln (200mV/mV) i.e. ln 200