hey so its just some rearranging that you need to do
784 = 2^? x 7^2
start by dividing both sides by 49 (7^2) which gives you:
16 = 2^?
Now there is a way to solve this on the calculator (idk if you've learnt how to though) but anyway just think what power of 2 makes 16? well its 2^4 (2x2x2x2 = 16) therefore
? = 4
hope that helps
784 = 2^? x 7^2
start by dividing both sides by 49 (7^2) which gives you:
16 = 2^?
Now there is a way to solve this on the calculator (idk if you've learnt how to though) but anyway just think what power of 2 makes 16? well its 2^4 (2x2x2x2 = 16) therefore
? = 4
hope that helps
Original post by purple_1710
hey so its just some rearranging that you need to do
784 = 2^? x 7^2
start by dividing both sides by 49 (7^2) which gives you:
16 = 2^?
Now there is a way to solve this on the calculator (idk if you've learnt how to though) but anyway just think what power of 2 makes 16? well its 2^4 (2x2x2x2 = 16) therefore
? = 4
hope that helps
784 = 2^? x 7^2
start by dividing both sides by 49 (7^2) which gives you:
16 = 2^?
Now there is a way to solve this on the calculator (idk if you've learnt how to though) but anyway just think what power of 2 makes 16? well its 2^4 (2x2x2x2 = 16) therefore
? = 4
hope that helps
thank you
hey so I'm not entirely sure but I think its this:
you need to first of all find what value turns y into x and vice versa so I'll use k as the unknown value
y = k x 1/x = k/x here you need to find k so for that you use the first set of values given to you.
20 = k/3 just resolve that to give you
k = 3x20 = 60 now you re-use that formula, knowing y and knowing k to find x
12 = 60/x resolve that
x = 60/12
x = 5
I think this is how you do it, I hope I explained it all right, but I would just check with someone else in case I'm wrong
you need to first of all find what value turns y into x and vice versa so I'll use k as the unknown value
y = k x 1/x = k/x here you need to find k so for that you use the first set of values given to you.
20 = k/3 just resolve that to give you
k = 3x20 = 60 now you re-use that formula, knowing y and knowing k to find x
12 = 60/x resolve that
x = 60/12
x = 5
I think this is how you do it, I hope I explained it all right, but I would just check with someone else in case I'm wrong
Quick Reply
Related discussions
- what supplies for year 10?
- surviving (hopefully) sixth form | year 12 journal
- Should I transfer to my local school or stay at Harris Westmister?
- how to keep the info in ur head long term
- yr13 journal
- Should I go dixons or Greenhead college
- Heriot-watt or edinburgh?!
- Creating The Future Of Our Dreams - Study23 GYG
- Going into year 11
- Official Heriot-Watt University 2023 Applicant Thread
- What is the best online/distance a level provider?
- need help
- us uni
- Have any questions about University?
- Year 10 advice
- i want to switch my options helppp !!!! pyschology --> photography
- len's y12 gyg blog
- Send me your maths questions!
- Dentistry Interview, A levels. I'm stuck
- How do I manage my time in sixth form?
Latest
Trending
Last reply 2 days ago
went from 3s to 9s with (literally) night before revision - ask me anythingGCSEs
59
Trending
Last reply 2 days ago
went from 3s to 9s with (literally) night before revision - ask me anythingGCSEs
59
