Question:The radius of the Earth’s orbit about the Sun is 1.50 × 1011 m.Calculate the mass of the Sun.
Previous part of the question got you to to get the equation: 4pi^2/GMsun=T^2/r^3
T = 1 year = 3.16 × 107s [1]
ms = 4π2r 3/GT2 = [4π2 × (1.50 × 1011)3]/
[6.67 × 10–11 × (3.16 × 107) Rest of subs [1]
Mass of Sun = 2.00 × 1030kg [1] [3] 12
I can see how they got the answer. However initially i didn't get the previous part. So I attempted to answer the equation using the formula:
gravity=GMsun/r^2
so 9.81=6.67*10^-11(Msun)/(1.5*10^11)^2 giving an anser of 3.31*10^33kg. Could anyone explain why the second method is incorrect.