fyaa79
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A cube of ice has a mass 𝑚𝑚 = 0.184 kg and is at a temperature 𝑇 = −20.0℃. The, • specific heat of ice 𝑐i = 2090 Jkg–1• latent heat of fusion of ice is 𝐿𝑓(𝑖𝑒) = 3.33 × 105 Jkg–1 • specific heat of water 𝑐w = 4190 Jkg–1 K–1 • latent heat of vaporisation of water 𝐿𝑣(𝑤) = 22.6 × 105 Jkg–1 How much heat is required to change this ice into steam?
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RogerOxon
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What have you tried so far? This is a help forum, not a homework service.
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fyaa79
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Not really sure where to begin.

I have tried calculating Q = mLf for ice and Q = mLv but don't think that is right.


(Original post by RogerOxon)
What have you tried so far? This is a help forum, not a homework service.
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RogerOxon
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(Original post by fyaa79)
Not really sure where to begin.

I have tried calculating Q = mLf for ice and Q = mLv but don't think that is right.
You have several steps:
1. Heat the ice to 0C
2. Turn it into water at 0C
3. Heat the water to 100C
4. Turn it into steam

How much energy does each stage take?
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