Back
to top
Heat Capacities Questions
Watch
Announcements
Page 1 of 1
Go to first unread
Skip to page:
A cube of ice has a mass 𝑚𝑚 = 0.184 kg and is at a temperature 𝑇 = −20.0℃. The, • specific heat of ice 𝑐i = 2090 Jkg–1• latent heat of fusion of ice is 𝐿𝑓(𝑖𝑒) = 3.33 × 105 Jkg–1 • specific heat of water 𝑐w = 4190 Jkg–1 K–1 • latent heat of vaporisation of water 𝐿𝑣(𝑤) = 22.6 × 105 Jkg–1 How much heat is required to change this ice into steam?
0
reply
Not really sure where to begin.
I have tried calculating Q = mLf for ice and Q = mLv but don't think that is right.
I have tried calculating Q = mLf for ice and Q = mLv but don't think that is right.
(Original post by RogerOxon)
What have you tried so far? This is a help forum, not a homework service.
What have you tried so far? This is a help forum, not a homework service.
0
reply
Report
#4
(Original post by fyaa79)
Not really sure where to begin.
I have tried calculating Q = mLf for ice and Q = mLv but don't think that is right.
Not really sure where to begin.
I have tried calculating Q = mLf for ice and Q = mLv but don't think that is right.
1. Heat the ice to 0C
2. Turn it into water at 0C
3. Heat the water to 100C
4. Turn it into steam
How much energy does each stage take?
0
reply
X
Page 1 of 1
Go to first unread
Skip to page:
Quick Reply
