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Maths revision

I have a test in less than a week for maths and was looking through an old test I had done. I found that my weakest point is proving something algebraically. The question was:
Prove algebraically that the difference between the squares of any two consecutive integers is equal to these two integers. I did try to attempt this question but completely sucked at it. :P any help is greatly appreciated many thanks :smile:
if you have a number n n then the next number is n+1 n + 1, the difference between the squares is (n+1)2n2(n+1)^2 - n^2

Now make an equation relating to the addition of nn and it's consecutive number and they should be equal for them to be the same.
(edited 7 years ago)
Reply 2
Original post by NotNotBatman
if you have a number n n then the next number is n+1 n + 1, the difference between the squares is (n+1)2n2(n+1)^2 - n^2

Now make an equation relating to the difference between n and it's consecutive number and the should be equal for them to be the same.


Thanks so much that helped explain it a lot !!

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