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I'm pretty sure the tan^2 question only gave you 3 values
For the translation I put -10 not -2
How is it -2?


And btw hats off to u for storing all the answers in ur calculator, i run out of time just doing the papar let alone making note of my answers to help others haha
Original post by sadeqrahman
yeah, I got 2 values at the end, is that right?


tan^-1(sqrt(3/2) = 50.1

tan^-1(-sqrt(3/2) = -50.1 < +180 = 129.2

Surely these are the only solutions between 0 and 180?
Anyone know any sixth forms or sixth form colleges that will take a year 12 student to retake his AS-year and then do A2? Around London, like more near essex.
(edited 9 years ago)
Original post by Chloe<3
For the translation I put -10 not -2
How is it -2?


And btw hats off to u for storing all the answers in ur calculator, i run out of time just doing the papar let alone making note of my answers to help others haha


I didn't notice this trick in the exam either, but translating in the x-direction is f(x+k) it was something like 5(x-2) expands out to give the translation of 10.
Reply 185
Original post by HesitantCicada
tan^-1(sqrt(3/2) = 50.1

tan^-1(-sqrt(3/2) = -50.1 < +180 = 129.2

Surely these are the only solutions between 0 and 180?


You are told tan2(2θ)=32tan^2(2\theta) = \dfrac{3}{2}, but if you square root that you get tan(2θ)=±32tan(2\theta) = \pm\sqrt{\dfrac{3}{2}}, which when you evaluate produces 4 answers in the correct range.

[br]tan(2θ)=±32[br]2θ=50.7,50.7(working angles)[br]2θ=50.7,230.7,129.3,309.3[br]θ=25,115,65,155[br][br]tan(2\theta) = \pm\sqrt{\dfrac{3}{2}}[br]2\theta = 50.7, -50.7 \text{(working angles)}[br]2\theta \therefore = 50.7, 230.7, 129.3, 309.3[br]\theta \therefore = 25, 115, 65, 155[br]
I'm pretty sure the tan^2 question only gave you 3 values
Original post by Doomlar
You are told tan2(2θ)=32tan^2(2\theta) = \dfrac{3}{2}, but if you square root that you get tan(2θ)=±32tan(2\theta) = \pm\sqrt{\dfrac{3}{2}}, which when you evaluate produces 4 answers in the correct range.

[br]tan(2θ)=±32[br]2θ=50.7,50.7(working angles)[br]2θ=50.7,230.7,129.3,309.3[br]θ=25,115,65,155[br][br]tan(2\theta) = \pm\sqrt{\dfrac{3}{2}}[br]2\theta = 50.7, -50.7 \text{(working angles)}[br]2\theta \therefore = 50.7, 230.7, 129.3, 309.3[br]\theta \therefore = 25, 115, 65, 155[br]

Are we certain it was tan(2x)? I must've missed that, I've scored 100UMS on every practice I've done and I've probably gotten an optimistic 64 marks on this... Lucky me.
Couple of questions
Would I drop a mark for leaving out the +C on the integration? As I know that sometimes it's not required on the mark scheme
Also I guessed that q=3 and wrote that down a log with a load of working that didn't get me to the answer
Will I get a mark for the answer even though it's just guessed?


Posted from TSR Mobile
I'm pretty sure the tan<2 question only gave you 3 values
Reply 190
For the area of the integral, I don't see how it was 49/10. I can't remember what wrote in the exam but i recalculated it and got 31/6. You get 1 + 2 + 2/3 + 3/2 = 31/6.
Reply 191
Original post by Ellios
Couple of questions
Would I drop a mark for leaving out the +C on the integration? As I know that sometimes it's not required on the mark scheme
Also I guessed that q=3 and wrote that down a log with a load of working that didn't get me to the answer
Will I get a mark for the answer even though it's just guessed?


Posted from TSR Mobile


To answer your first question, it really depends how everyone else did; if everyone did well on that question and put +c then they will require +c, otherwise yeah you may get the mark.

I'm not sure for your second question; sometimes they say you have to have a correct method but who knows :/
Original post by Ellios
Couple of questions
Would I drop a mark for leaving out the +C on the integration? As I know that sometimes it's not required on the mark scheme
Also I guessed that q=3 and wrote that down a log with a load of working that didn't get me to the answer
Will I get a mark for the answer even though it's just guessed?


Posted from TSR Mobile


I doubt that you would get the A1 mark as the mark schemes usually request the full equation plus the q= for questions like these for the A1 mark
I'm pretty sure the tan2 question only gave you 3 values
Reply 194
Original post by BlackLipBastard
I'm pretty sure the tan^2 question only gave you 3 values

Original post by BlackLipBastard
I'm pretty sure the tan^2 question only gave you 3 values

Original post by BlackLipBastard
I'm pretty sure the tan<2 question only gave you 3 values

Original post by BlackLipBastard
I'm pretty sure the tan2 question only gave you 3 values


See:

Original post by Doomlar
You are told tan2(2θ)=32tan^2(2\theta) = \dfrac{3}{2}, but if you square root that you get tan(2θ)=±32tan(2\theta) = \pm\sqrt{\dfrac{3}{2}}, which when you evaluate produces 4 answers in the correct range.

[br]tan(2θ)=±32[br]2θ=50.7,50.7(working angles)[br]2θ=50.7,230.7,129.3,309.3[br]θ=25,115,65,155[br][br]tan(2\theta) = \pm\sqrt{\dfrac{3}{2}}[br]2\theta = 50.7, -50.7 \text{(working angles)}[br]2\theta \therefore = 50.7, 230.7, 129.3, 309.3[br]\theta \therefore = 25, 115, 65, 155[br]
Original post by HesitantCicada
tan^-1(sqrt(3/2) = 50.1

tan^-1(-sqrt(3/2) = -50.1 < +180 = 129.2

Surely these are the only solutions between 0 and 180?

Nah if you noticed, in the equation where it said hence, it was slightly different to the original. It had a 2 so for your working out you would times the 180 to give you 360, work out the values and then divide by 2 at the end
Does anyone remember what the actual questions for 2bi and 9c were?
TSR repeating my posts smh
Reply 198
Original post by BlackLipBastard
TSR repeating my posts smh


Haha no worries! :P

Original post by rockon8912
Does anyone remember what the actual questions for 2bi and 9c were?


2)b)i) was finding the coefficient of the y2y^2 term in the expansion of (1+y)3(1+y)^3
9)c) I can't remember sorry :/
Reply 199
Original post by BlackLipBastard
I'm pretty sure the tan2 question only gave you 3 values


It would give you 4. One above the axis between 0 and 45, one below between 45 and 90, another above between 90 and 135, and another below between 135 and 180.

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