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GCSE Chemistry Help

Please can someone help me with this question? Or send a mark scheme? I don't understand this

Thank you !
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(edited 6 years ago)
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What’s the question?
Reply 3
Original post by Bathila
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What’s the question?



Original post by thekidwhogames
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Sorry I have added a link https://pasteboard.co/HfxmPLrh.jpg
Original post by Odavies11
Sorry I have added a link https://pasteboard.co/HfxmPLrh.jpg


In solution the ions you have area:

Ag+
NO3-
H+
OH-

At cathode, the least reactive element is discharged; so either Ag+ or H+ cations will be reduced. Which one...?

At anode, the halide ions are oxidised and if not, the hydorixde ions are oxidised forming oxygen and water. So you make...?
Reply 5
Original post by thekidwhogames
In solution the ions you have area:

Ag+
NO3-
H+
OH-

At cathode, the least reactive element is discharged; so either Ag+ or H+ cations will be reduced. Which one...?

At anode, the halide ions are oxidised and if not, the hydorixde ions are oxidised forming oxygen and water. So you make...?


Would it be silver at the cathode?

and oxygen and water at the anode?
(edited 6 years ago)
Original post by Odavies11
Would it be silver at the cathode?


Precisely and the half equation is...?
Original post by thekidwhogames
In solution the ions you have area:

Ag+
NO3-
H+
OH-

At cathode, the least reactive element is discharged; so either Ag+ or H+ cations will be reduced. Which one...?

At anode, the halide ions are oxidised and if not, the hydorixde ions are oxidised forming oxygen and water. So you make...?


Original post by Odavies11
Would it be silver at the cathode?

and oxygen and water at the anode?

Yes but I think you'd just say oxygen gas formed at the anode instead of oxygen and water
Original post by savage_queen
Yes but I think you'd just say oxygen gas formed at the anode instead of oxygen and water


True but I'd say both just in case
Reply 9
Original post by thekidwhogames
Precisely and the half equation is...?


would the half equation at the cathode be Ag+ + e- -> Ag

and the anode 4OH- -> O2 +2H2O + 4e-
Original post by Odavies11
would the half equation at the cathode be Ag+ + e- -> Ag

and the anode 4OH- -> O2 +2H2O + 4e-


Well done - correct! :smile:
Reply 11
Original post by thekidwhogames
Well done - correct! :smile:


Brilliant! Thanks so much for the help!

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