This is straight from the Edexcel A2 Student's Book. I would normally use K.E. = eV for questions like this, but that won't work here. I don't understand how to solve this. It's a cyclotron, so perhaps I could use r = mv/Bq, but I don't know B.
Qu 2. Yes, if the charged particle is performing circular motion, the key is to equate its centripetal force mv2/r to the the force on a moving charge in a magnetic field, Bqv This gives you the relationship between the radius of the path, its velocity and the field strength.
Qu 2. Yes, if the charged particle is performing circular motion, the key is to equate its centripetal force mv2/r to the the force on a moving charge in a magnetic field, Bqv This gives you the relationship between the radius of the path, its velocity and the field strength.
Yes, but um, the field strength is not given in the question. How would I calculate the speed without it?
27km distance (27,000m) 11,000 times a second. 1/11,000s for 27km, speed = distance/time, speed = 27,000/(1/11,000) and I don't have a calculator to hand haha, but that might be the speed?
27km distance (27,000m) 11,000 times a second. 1/11,000s for 27km, speed = distance/time, speed = 27,000/(1/11,000) and I don't have a calculator to hand haha, but that might be the speed?
Okay. OKAY. REALLY embarrassed right now, but okay, yes, that's exactly it, that gives the answer. xD Um. Wow. Okay. xD Thank you so much!
But that doesn't seem to help much with Q.2 either. :/
Um, sorry, but that was my full working for question 2.
eV =1/2mv^2 (the formula)
1MeV = 1 x 10^6 x 1.6 x 10^-19 (Finding the energy in Joules)
1 x 10^6 x 1.6 x 10^-19 = 0.5 x 1.67 x 10^-27 x v^2 (Putting the values in the formula) =1.38 x 10^7 (The answer)
However, the correct ans given in the book is 1.96 x 10^7.
I realised that and deleted my original post. As you can see. I thought initially you were giving the answer to the final part of the question, the bit you originally asked about. Unfortunately you have replied to something I deleted.
Yes. I get the same answer. Sometimes mark schemes or book answers can be wrong or misprinted. What value does that give for the magnetic field? Does it agree with the book answer? You can check by trying both your answer and the given answer to find the value to the other part.
I realised that and deleted my original post. As you can see. I thought initially you were giving the answer to the final part of the question, the bit you originally asked about. Unfortunately you have replied to something I deleted.
Yes. I get the same answer. Sometimes mark schemes or book answers can be wrong or misprinted. What value does that give for the magnetic field? Does it agree with the book answer? You can check by trying both your answer and the given answer to find the value to the other part.
All the other answers correspond to the first answer given in the book, none of them work with my value. But okay, atleast now I know I didn't go completely wrong somewhere. Thank you so much for your time.