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Electron Deceleration

My textbook states the following: When an electron strikes the metal, it will be attracted towards the nucleus of an atom in the metal. This will cause it to change both its speed and direction - in other words, it decelerates.

But I fail to see why the electron decelerates. They electron is attracted to the nucleus. So it must accelerate towards the nucleus right? And once it collides with the nucleus, it must lose its energy and stick to the nucleus. What am I missing?
Original post by esrever
My textbook states the following: When an electron strikes the metal, it will be attracted towards the nucleus of an atom in the metal. This will cause it to change both its speed and direction - in other words, it decelerates.

But I fail to see why the electron decelerates. They electron is attracted to the nucleus. So it must accelerate towards the nucleus right? And once it collides with the nucleus, it must lose its energy and stick to the nucleus. What am I missing?

What is the context?

See here for a maybe relevant extract: http://www.columbia.edu/itc/hs/dental/sophs/material/production_xrays.pdf
its an inelastic collision?
Reply 3
Original post by superimoji
its an inelastic collision?


I am not sure about that
Reply 4
Original post by BobbJo
What is the context?

See here for a maybe relevant extract: http://www.columbia.edu/itc/hs/dental/sophs/material/production_xrays.pdf


You guessed it correctly! This was regarding x-rays. Thank you for the pdf :smile:.
Original post by esrever
I am not sure about that


kinetic energy is not comserved and the particle slows down aka decelrates? I dont know. Where do you find these questions. I am doing edexcel.
Reply 6
Original post by superimoji
kinetic energy is not comserved and the particle slows down aka decelrates? I dont know. Where do you find these questions. I am doing edexcel.


I am doing CIE. I have a chapter on medical imaging.
Original post by esrever
I am doing CIE. I have a chapter on medical imaging.

https://www.youtube.com/watch?v=T1WwHh4b__M
Visual explanation here
Reply 8


The link was quite useful :smile:

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