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    It's one of those days. Any help appreciated

    The wheel of the London Eye had a diameter of 130m and takes 30 minutes to complete 1 revolution. Calculate the change due to the rotation of the wheel of the support force on a person of weight 500N in a capsule at the top of the wheel.

    So I understand that the centripetal force is the difference of the weight and the support force
    F=mg-S
    S=mg-F
    I can calculate F from mv^2/r
    How do I calculate the change from what reference points?
    Answer is -0.04N




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    (Original post by tmorrall)
    It's one of those days. Any help appreciated

    The wheel of the London Eye had a diameter of 130m and takes 30 minutes to complete 1 revolution. Calculate the change due to the rotation of the wheel of the support force on a person of weight 500N in a capsule at the top of the wheel.

    So I understand that the centripetal force is the difference of the weight and the support force
    F=mg-S
    S=mg-F
    I can calculate F from mv^2/r
    How do I calculate the change from what reference points?
    Answer is -0.04N




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    At the top the centripetal force is the difference between the weight (down) and the support (up)
    C = W - S
    At the bottom the centripetal force is the difference between the support (up) and the weight (down)
    C = S - W
    It's the difference in the support (rearrange the equation for this) at the top and the support at the bottom that you want.
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    So I am not going crazy! Right I cant get the answer the text book has stated but the method is sound I am going get some people to try it out see what they get and compare. Thanks!


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