Equation arrangement internal resistance
If you're given the equation e/v = r/R + 1 how would you re arrange this to find r?
So far I've done,
E/v - 1 = r/R
Then (e-v)/v = r/R
So from here do the v's just cancel out to give you -eR=r ???
Just a little unsure.
Posted from TSR Mobile
So far I've done,
E/v - 1 = r/R
Then (e-v)/v = r/R
So from here do the v's just cancel out to give you -eR=r ???
Just a little unsure.
Posted from TSR Mobile
Original post by claudisx
If you're given the equation e/v = r/R + 1 how would you re arrange this to find r?
So far I've done,
E/v - 1 = r/R
Then (e-v)/v = r/R
So far I've done,
E/v - 1 = r/R
Then (e-v)/v = r/R
Now multiply both sides by R
That's what I did, so them the answer would be -eR = r ?
The v's cancel out right?
Posted from TSR Mobile
The v's cancel out right?
Posted from TSR Mobile
Original post by claudisx
That's what I did, so them the answer would be -eR = r ?
The v's cancel out right?
Posted from TSR Mobile
The v's cancel out right?
Posted from TSR Mobile
Nope. Leave the v terms. They don't cancel.
(e-v)/v can be written as
e/v - v/v which is
e/v - 1 (which is what you had originally)
but the v stays.
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