The method I proposed to "prove" the proportionality holds is fine, but they're more interested in you actually calculating the potential at two radii
r1,r2 and showing that they equal the points on the graph (sorry- I should have checked the MS to pick up on this!
What they want is for you to use the normal formula of V(r) and calculate it for at least 2 points on the graph, showing it works.This is just how I would have done it since it seems less reliant on knowing the mass of the body involved.) Anyhow, here's a graphical example of how it works (code snippet attached.)
The example case is the Earth: I've plotted the potential over radius as that black line. The blue points I've given are 5 randomly generated points in
r and I've plotted them up for you. They're sorted in ascending order.
You know that
V∝r1 and hence will find that
V2V1=r1r2, thusly
V2V1r1=r2. Using the first randomly generated point on the curve as
r1,V1, and the
V2 for each succeeding randomly generated point, I've used the proportionality to try and calculate
r2 for each succeeding randomly generated point. I then plot all the "guesses".
These guesses rely only on the initial point I picked on the curve, and the notion that it is indeed a
r1 curve. The guesses match the curve, which implies that potential does indeed scale as
r1 (I would hope it would since that's what I gave it to graph in the first place!
)
The reason I'd have chosen this method is because typically I'm not confident in my previous answers- this method avoids the requirement of knowing the mass of the body involved. If you messed up getting the mass, this method wouldn't fault you. That being said, if you got the mass wrong it's unlikely you'd be able to pull this off foolproof anyway