Ok So im confused on Q15a Paper 1 2020, Edexcel A-level. Any help would be appreciated.
Based of this circuit to me it looks as though once the capacitor is charged, current would stop flowing. However the MS shows the charging curve of a capacitor. Why would that be the case, wouldn't it be a capacitor discharge curve as the capacitor charges it takes pd from every other circuit. Also would there be any significance of Y being an integrated circuit. I'm having a hard time understanding the question.
The setup for the question says the capacitor is initially discharged, from inspection of the circuit diagram it should be clear that S1 is initially open and that the capacitor will begin to charge through the resistors in series when S1 is closed.
The setup for the question says the capacitor is initially discharged, from inspection of the circuit diagram it should be clear that S1 is initially open and that the capacitor will begin to charge through the resistors in series when S1 is closed.
Im just unclear why the p/d of Y would be the same as the capacitor