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FSMQ Additional Maths help

Hi, I' doing an additional maths past paper and don't know how to do this five mark question:
Solve the equation 5sin2x=2cos2x in the interval 0<x<360
Give your answers correct to one decimal place.

(the more than and less than signs should be including 0 and 360)
Thank you!
Reply 1
Original post by xxjessietxx
Hi, I' doing an additional maths past paper and don't know how to do this five mark question:
Solve the equation 5sin2x=2cos2x in the interval 0<x<360
Give your answers correct to one decimal place.

(the more than and less than signs should be including 0 and 360)
Thank you!


so you know the trigonometric identity : sinx / cosx = tanx ?

use this:

divide both sides by cos2x

so 5sin2x/cos2x = 2cos2x/cos2x
5tan2x = 2
tan2x = 0.4
2x = tan^-1(0.4)
= 21.8 , 201.8, 381.8, 561.8(, 741.8) (degrees)
(because it's 2x, limit is now 720 degrees)
x = 10.9, 100.9, 190.9, 280.9(, 370.9)
because range is from 0-360 degrees, x = 10.9, 100.9, 190.9, 280.9 (degrees)

hope that helps :smile:
(edited 8 years ago)
Reply 2
Thank you that makes sense now :smile: xxx
Reply 3
Original post by xxjessietxx
Thank you that makes sense now :smile: xxx


No worries :smile: How long have you been learning the content for Additional Maths?
Reply 4
I started last year but we only have one lesson a week and there's only four of us doing it :smile:

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