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# What are the most difficult M1 questions you have come across?

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1. Preferably edexcel.

Spoiler:
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Spoiler:
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"A ball is projected vertically upwards from a point with a speed m/s. At the same time a second ball is dropped from a height of 40m vertically above . Given that the balls have the same speed when they collide, find the time at which they collide."
2. Q3 on this paper. It is great fun!

It tests almost everything you need to know for pulleys and scale pans
3. (Original post by Cryptokyo)
Q3 on this paper. It is great fun!

It tests almost everything you need to know for pulleys and scale pans
Sounds fun, I'll give it a go now thanks.
4. (Original post by KloppOClock)
Preferably edexcel.

A ball is projected vertically upwards from a point with a speed m/s. At the same time a second ball is dropped from a height of 40m vertically above . Given that the balls have the same speed when they collide, find the time at which they collide.
5. (Original post by Cryptokyo)

A ball is projected vertically upwards from a point with a speed m/s. At the same time a second ball is dropped from a height of 40m vertically above . Given that the balls have the same speed when they collide, find the time at which they collide.
Do you have the mark scheme for that, I tried to do it but I ended up with two times of -0.58s and -3.5 seconds
6. (Original post by KloppOClock)
Do you have the mark scheme for that, I tried to do it but I ended up with two times of -0.58s and -3.5 seconds
You could post your working and we can check it.
7. (Original post by KloppOClock)
Do you have the mark scheme for that, I tried to do it but I ended up with two times of -0.58s and -3.5 seconds
Solution in spoiler.
Spoiler:
Show
For same speed:

Displacement SUVATS

Equate SUVATS

Sub in

So
8. (Original post by notnek)
You could post your working and we can check it.
Sure, I did it again and this time I got 10/7 seconds, although I'm not sure wha tthe correct solution is.
9. (Original post by Cryptokyo)
Solution in spoiler.
Spoiler:
Show
For same speed:

Displacement SUVATS

Equate SUVATS

Sub in

So
ahh sound, i think i just messed up one of my substitutions in my first attempt.
10. KloppOClock
Don't know if you have done them already but here is a link to tiered M1 papers. The gold ones are best.
11. Here is a link to some resources made by the user TeeEm.
(Original post by KloppOClock)
Preferably edexcel.
12. (Original post by KloppOClock)
ahh sound, i think i just messed up one of my substitutions in my first attempt.
Now you can do it you should pray that a similar question comes up in the real thing!

You would be part of a small minority who could do it.
13. (Original post by Cryptokyo)
Here is a link to some resources made by the user TeeEm.
That looks good.

Do you know where I can find a complete definition list for M1.
The only one I have is blank.

14. (Original post by notnek)
Now you can do it you should pray that a similar question comes up in the real thing!

You would be part of a small minority who could do it.
ha if only, im just praying everyone messes up so they can lower the grade boundaries for me.
15. (Original post by KloppOClock)
Preferably edexcel.
Here is a paper I made ages ago. If you wanna have a go.

Ignore the definition question
Attached Images
16. Mechanics 1 Practice Paper 4.pdf (509.4 KB, 50 views)
17. (Original post by KloppOClock)
That looks good.

Do you know where I can find a complete definition list for M1.
The only one I have is blank.

Here is a powerpoint with all of that info
Attached Files
18. 1-mathematical-modelling.ppt (815.5 KB, 315 views)
19. (Original post by Cryptokyo)
Here is a powerpoint with all of that info
Cheers, I tried to google for it before and couldn't find anything.
20. (Original post by KloppOClock)
Sure, I did it again and this time I got 10/7 seconds, although I'm not sure wha tthe correct solution is.
why is it s-40 and not 40-s, s-40 will give you a negative distance?
21. (Original post by Dominator1)
why is it s-40 and not 40-s, s-40 will give you a negative distance?
Well that depends on which direction you take as positive.

Negative displacement is fine since it's a vector quantity.

But you're right that there is a mistake in the working. One of the displacement equations uses negative acceleration and the other uses positive.
22. (Original post by notnek)
Well that depends on which direction you take as positive.

Negative displacement is fine since it's a vector quantity.

But you're right that there is a mistake in the working. One of the displacement equations uses negative acceleration and the other uses positive.
the acceleration is fine, since one is accelerating and the other is decelerating. I was wondering about the distance because if it's the case of displacement being a vector then the two balls wouldn't have had the same velocity (because they're travelling opposite directions), they would have the same speed.
Then:
v=u-9.8t and -v=9.8t, making u=0

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