eleastic potential energy

a 200g object is on the end of a spring constant of 2.5N/m. calculate the elastic potential energy stored in the spring?

Im gonna assume that one end of the spring is fixed and that the particle is hanging in equilibrium directly below the point of suspension.

Firstly i recommend drawing a diagram and labelling all the forces clearly. From there note that the particle is hanging in equilibrium. What does this tell you about the resultant force on the particle?

Now you should be in a position to find x the extension. Then its just a matter if plugging your x value into the correct formula for elastic potential energy.

Let me know if u didn’t get any bits.

don't want to be rude but can you exlain me that wiht some equation please

convert 200g into newtons- 10N=1kg
from this you can work out the extension by muliplying 2.5N/m by 2N
=5 metres
EPE=1/2 ke^2
1/2 x 2.5 x 5^2
=31.25
(I think)

This is wrong.

convert 200g into newtons- 10N=1kg
from this you can work out the extension by dividing 2N by 2.5N/m
=0.8 metres
EPE=1/2 ke^2
1/2 x 2.5 x 0.8^2
=0.8J
(I think)

thanks please what EPE mean?

elastic potential energy
sorry I've edited the answer

convert 200g into newtons- 10N=1kg
from this you can work out the extension by dividing 2N by 2.5N/m
=0.8 metres
EPE=1/2 ke^2
1/2 x 2.5 x 0.8^2
=0.8J
(I think)

don't worry but thanks again but 200g is 0.2kg now what shou i do?

F= kx
so 1.962/2.5
Right?

if 10 Newtons=1kg
0.2kg=...

2N thanks again

why did u use 1.962 and not 2??? Doesn't 10 Newtons=1kg

oh yeah !!! I quite forgot! In my gcses i used to use 10 N but now in my AS its 9.81... doesnt matter...

thanx for the clarification :P

a 200g object is on the end of a spring constant of 2.5N/m. calculate the elastic potential energy stored in the spring?