A battery of e.m.f 6 V is connected across a resistor of resistance 12 ohms. The potential difference across the resistor is 4.5 V.
What is the internal resistance of the battery?
A) 3 ohms
B) 4 ohms
C) 9 ohms
D) 16 ohms
I worked out the current across the resistor which is the same across the battery, by doing I = 4.5/12 = 3/8
As the resistor has an p.d of 4.5 the battery must have a p.d of 1.5, as sum of e.m.f = sum of p.d
So I used E = V + Ir, with the values 6 = 1.5 + 3/8r to get r as 12 ohms, which isn't an answer.
So I then used E = I(R+r), with the values 6 = 3/8(12+r) to get r as 4, which is B)
My question is why has the 1st method not worked and did I even get the right answer using the 2nd method?