Electrcity Help
I understand one of the ways the markscheme showed how to do it (comparing ratios of resistances, and therefore voltages) but I dont see where I've gone wrong either. Any help would be very much appreciated
The whole of the 1.5V cell EMF isn't dropped across the internal resistance - just 0.2V on each one to leave the 1.3V
current in each internal resistor is 0.2/0.65 (or 4/13 if you prefer) Amps
current in lamp is twice the current in one internal resistor 0.4/0.65 (8/13) Amps
so power dissipated by lamp is 1.3 V * 8/13 A = 0.8W
current in each internal resistor is 0.2/0.65 (or 4/13 if you prefer) Amps
current in lamp is twice the current in one internal resistor 0.4/0.65 (8/13) Amps
so power dissipated by lamp is 1.3 V * 8/13 A = 0.8W
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