Power and energy supply to a resistor help please!

Right so for 2) d) I worked out the p.d. lost as 2000V, and then did 120000V - 2000V = 118000 V = 118 kV as the p.d. supplied to the town.

Then for 2) e) I used Ohm's law and did 118000/500 = 236 ohms, both right?

And for the efficiency what would it be?

That looks fine.

The efficiency I gave you earlier way back in post #13.

So (59/60) x 100 = 98.3%?

That's it.
The station starts with 60MW and the town gets 59MW because 1MW is lost in the cables.

Question done.
You got most of it right without our help. Just a couple of hints needed.

When you have problems with questions, always show what you have attempted, even if you think it's all wrong.
If you do, there are plenty of people on here who will be willing to help.