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Expanded form of equation of a circle

Find the equation of each circle with given centre and radius, write your answer without brackets in simplest form.

(1,2) r=4

I got x2+y2-2x-4y+1=0

Apparently that should be a -11 not a +1.

for (5,-1) r=3

I got x2+y2+10x+2y+23=0
That should be a +17, not a +23.

Unsure where I am going wrong....I have all the other terms correct....so don't understand where I am "falling down/going wrong" with the constant term.
Original post by apronedsamurai
Find the equation of each circle with given centre and radius, write your answer without brackets in simplest form.

(1,2) r=4

I got x2+y2-2x-4y+1=0

Apparently that should be a -11 not a +1.

for (5,-1) r=3

I got x2+y2+10x+2y+23=0
That should be a +17, not a +23.

Unsure where I am going wrong....I have all the other terms correct....so don't understand where I am "falling down/going wrong" with the constant term.


equation of a circle with centre (a,b) and radius r is
Unparseable latex formula:

\(x-a)^2+(y-b)^2=r^2


Note the riht hand side is r2r^2
I suspect you are just putting r here.
Reply 2
Original post by apronedsamurai
Find the equation of each circle with given centre and radius, write your answer without brackets in simplest form.

(1,2) r=4

I got x2+y2-2x-4y+1=0

Apparently that should be a -11 not a +1.

for (5,-1) r=3

I got x2+y2+10x+2y+23=0
That should be a +17, not a +23.

Unsure where I am going wrong....I have all the other terms correct....so don't understand where I am "falling down/going wrong" with the constant term.


have you included the radius squared in the right hand side?

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