Hess' cycle for C2H4(g) + HBr(g) → C2H5Br(g)
C2H4(g) +52.3 ΔHf/kJ mol–1
HBr(g) –36.2 ΔHf/kJ mol–1
C2H5Br(g) -60.4
Use the data in the table above to calculate the standard enthalpy change for the following reaction.
C2H4(g) + HBr(g) → C2H5Br(g)
I already have the answer for this but I am very stuck on what the products would be at bottom of hess' cycle because there is a bromine attached to the hydrogen, can anyone help?
HBr(g) –36.2 ΔHf/kJ mol–1
C2H5Br(g) -60.4
Δ
Hf/kJ mol–1
Use the data in the table above to calculate the standard enthalpy change for the following reaction.
C2H4(g) + HBr(g) → C2H5Br(g)
I already have the answer for this but I am very stuck on what the products would be at bottom of hess' cycle because there is a bromine attached to the hydrogen, can anyone help?
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