enthalpy question

5. The enthalpy of combustion of ethanol is -1380 kJmol-1. Calculate the enthalpy of formation of ethanol, given that the enthalpies of formation of carbon dioxide and water are -393.7 and -285.9 kJmol-1 respectively.
This is from the A-level chemistry website! the answer is -265.1 but i can't seem to get it
My final calculation ends up being -1380 - 1645.1 which is wrong but doing +1380 - 1645.1 seems to get the right answer but i am not too sure how to get the +1380.
Can someone please help?

Did you create the equations for enthalpy of combustion and formation correctly?
Did you correctly combine them to make formation of ethanol?

Did you create the equations for enthalpy of combustion and formation correctly?
Did you correctly combine them to make formation of ethanol?

I'm so sorry but do you mind helping me with this one 😅
"When ethanol burns in oxygen under standard conditions, carbon dioxide, water and 1368 kJmol^-1 of energy are produced. Calculate the enthalpy of formation of ethanol, given that the enthalpies of formation of carbon dioxide and water are -393.7 and -285.9 kJmol^-1 respective"
the answer is -227.1. I tried doing the exact same method that you did for this question too but I'm still unable to get the answer.
(I think the different wording in the first half of this question is throwing me off as it says 1368 kjmol-1 of energy is produced. Is this basically the same as the enthalpy of combustion of ethanol? )

why does it equal -1368 when the energy produced is +1368?

Because it released energy, so is exothermic

Hiya mate, are you sure the answer is -227.1 and not -277.1? I got this by doing (2(-393.7)+3(-285.9))--1368

hello, the mark scheme said it is -227.1. I re did the question and got that answer 🙂.

I see, which answer did you get sorry?

-227.1

I don't understand how and I can't see a way which you get this, can you explain what you did please as my method works out to be -277.1? Thanks in advance.