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Tricky physics a level circuits question

For AS OCR physics A.
http://tinypic.com/r/2s85v75/9

The answer is 'C'. How?
Original post by teacher's pet
For AS OCR physics A.
http://tinypic.com/r/2s85v75/9

The answer is 'C'. How?


This question is as much about reading the question carefully as well as the calculation.

The question asks for the ratio Power dissipated in RPower supplied by the cell\mathrm {\frac{Power \ dissipated \ in \ R}{Power \ supplied \ by \ the \ cell}}

You could first find the total current (you should get 0.125A but we don't even need to calculate this in the final answer).

Then use (or simply go straight to) P=I2RP = I^2R

Total power supplied by the cell uses the sum of all the resistances in the circuit (3 + 7 + 2 Ohms = 12 Ohms)

The power dissipated in the resistance uses 7 Ohms.

Putting it all together you should get Ratio=I2RvariableI2Rtotal\mathrm {Ratio} = \frac{I^2R_{variable}}{I^2R_{total}}

The I2I^2 terms cancel leaving a ratio of:712=0.58\frac{7}{12} = 0.58
(edited 6 years ago)

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