Isaac Physics.

Any ideas how would you redraw this circuit?
https://isaacphysics.org/questions/phys19_c4a_q8?board=phys19_c4_add&stage=a_level

I’ve tried many different ways, but I can’t seem to find the equivalent resistance. I also think that if you have a resistor in parallel to an empty wire, that resistance doesn’t count? What do you get when you have a resistor in parallel to no resistors?

Reply 1

glacierboy

3

All of the resistors are parallel (if you look at the possible paths for charge carriers to travel). The equivalent resistance therefore can be worked out using the 1/(1/R1 + 1/R2…) formula which you would use for resistors in parallel.

Original post by depriveofsocial

Any ideas how would you redraw this circuit?
https://isaacphysics.org/questions/phys19_c4a_q8?board=phys19_c4_add&stage=a_level

I’ve tried many different ways, but I can’t seem to find the equivalent resistance. I also think that if you have a resistor in parallel to an empty wire, that resistance doesn’t count? What do you get when you have a resistor in parallel to no resistors?

I also think that if you have a resistor in parallel to an empty wire, that resistance doesn’t count?

I would recommend you think about this further.

You can try using PhET DC circuit simulation to "verify" it.
https://phet.colorado.edu/sims/html/circuit-construction-kit-dc-virtual-lab/latest/circuit-construction-kit-dc-virtual-lab_en.html

Isaac Physics.

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