the curve c has equation y = x squared + 3px + 8p where p is a real constant. the straight line L has equation y = 1 - 2x given that L does not intersect C find the set of possible values of p giving your answer in exact form

Original post by Mohamedbib

the curve c has equation y = x squared + 3px + 8p where p is a real constant. the straight line L has equation y = 1 - 2x given that L does not intersect C find the set of possible values of p giving your answer in exact form

So what do you think this implies in terms of solutions? Are there any real solutions?

Original post by olygilly

make x^2 +3px+8p = 1-2x and solve, getting a second grade eq which discriminant must be <0 bc they do not intersect (no real sol). You get 9p^2-20p+8<0. Solve for x and you get 0.523<x<1.699

It's like getting someone to do something for them - they won't learn if you do this.

Also, I haven't actually checked your working but from a first glance, looks ok.

(edited 1 month ago)

Original post by vnayak

While you may be correct, please allow the OP to solve it for themselves. Detail the steps involved to solve the question but no mention of numbers or doing the calculation for them.

It's like getting someone to do something for them - they won't learn if you do this.

Also, I haven't actually checked your working but from a first glance, looks ok.

It's like getting someone to do something for them - they won't learn if you do this.

Also, I haven't actually checked your working but from a first glance, looks ok.

While you may be correct, please allow the OP to solve it for themselves. Detail the steps involved to solve the question but no mention of numbers or doing the calculation for them.

It's like getting someone to do something for them - they won't learn if you do this.

Also, I haven't actually checked your working but from a first glance, looks ok.

It's like getting someone to do something for them - they won't learn if you do this.

Also, I haven't actually checked your working but from a first glance, looks ok.

Original post by chavvo

Looks like they've removed their post now, but the question asks for exact form, so wouldn't get any marks for a decimal approximation at the end!

Also, I don't know what it is but I always seem to mess up the discriminant. I can do it now but I used to actually have problems with it.

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