a) Will I get the same gradient if I ll convert the mm to m and then find ln of each?
b) Lets say (just imagine) we re plotting
ln(x/mm) against
y/mm, then will I have to convert the mm to m when finding out the gradient? And do i ve to convert to the SI unit (in general) when finding out gradients?
c) The equation is y=kx^n
so if they ll ask for the value of k then:
ln(y) = n ln(x) + ln (k)
then y-intercept is equal to ln (k) and to find k, just anti-log. Is this answer enough?
d) I just want to know (just like maybe i ll become quicker at finding scales) ... how do you look for it when finding the scale like the one in the image? What i do is just look at the first two figures like in ln(x) column to make it easier for me, it works actually coz the third firgure will appear in between the separation.
Just wanna make sure.