Maths Question

A line touches a circle at only one point, the co-ordinates of which are (3,3).

The centre of the circle is at the point (1,1).

What is the equation of the line?

I worked out the radius which is 2 root 2

Reply 1

mqb2766

You don't need the radius. You need a point on the line (given) and the gradient, so what in the question means you can get the gradient?

Reply 2

Jopping127

Original post by mqb2766

You don't need the radius. You need a point on the line (given) and the gradient, so what in the question means you can get the gradient?

idk im confused how would i start to work this question out?

Reply 3

mqb2766

Original post by Jopping127

idk im confused how would i start to work this question out?

You're told the line touches the circle at that point. So look up what that means and you can pretty much write the line gradient down.

Reply 4

Jopping127

Original post by mqb2766

You're told the line touches the circle at that point. So look up what that means and you can pretty much write the line gradient down.

okii ive done this but i have no clue if its right https://docs.google.com/document/d/1xEhRGdKOABY0Tk3XM0E_rWnNO7ig-FYD8B2Ac6tz9jU/edit?usp=sharing

Reply 5

mqb2766

Agree the line gradient is -1. You know (3,3) is on the line as well so you can get c.

Reply 6

ghostwalker

Original post by Jopping127

okii ive done this but i have no clue if its right https://docs.google.com/document/d/1xEhRGdKOABY0Tk3XM0E_rWnNO7ig-FYD8B2Ac6tz9jU/edit?usp=sharing

Since you have a gradient of -1, then the line

y=mx+c
becomes
y= -x + c
rather than what you have.

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